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Blababa [14]
2 years ago
6

Can someone help me right now plz

Mathematics
1 answer:
Vilka [71]2 years ago
6 0
Can you take a better pic i cant see the whole problem
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An observer (O) is located 500 feet from a school (S). The observer notices a bird (B) flying at a 39° angle of elevation from h
Serhud [2]

Answer:

h=404.89

Step-by-step explanation:

We are looking for side h, which is opposite of the observer. We know that the side adjacent to the observer is 500 feet. We also know that the angle from the observer to the bird is 39°. Because we have these values, SOH CAH TOA tells us that we should use tangent, opposite over adjacent.

We can set up our equation as follows:

tan(39°)=h/500

We can then solve for h:

500*tan(39°)=h

h=404.89

4 0
2 years ago
Help xd <br> -(x+2) =<br> 3(7x - 8)=<br> 7(x+3)-5x<br><br> Thank you!
HACTEHA [7]

Answer:

x=−5

x= 31/21 =1 10/21= 1.476190476

2x+21

hope this helps

3 0
3 years ago
Read 2 more answers
a crane lifts a 450 kg concrete to the top of a 50 m building in 5 s. assuming g=10 m/s² calculate a) the potential energy of th
Juliette [100K]

Answer:

Step-by-step explanation:

The work done changes the potential energy

ΔPE = mgΔh = 450(10)(50) = 225,000 = 225 kJ

power is the rate of doing work

P = 225000/5 = 45000 W = 45 kW

5 0
2 years ago
How do you get the numbers 4 5 13 to equal 5
MAVERICK [17]
You can subtract 4 from 13 then subtract 4 again
3 0
3 years ago
=
const2013 [10]

The equation in the given standard form is (x+10)^2+(y+6)^2=5^2

<h3>Equation of a circle</h3>

The standard equation of a circle is expressed as:

(x-a)^2+(y-b)^2=r^2

Given the equation x^2 + y^2 + 20x + 12y + 111 =0

Group the function to have:

(x^2 +20x)+(y^2+ 12y) + 111 =0

Complete the squares to have:

(x^2 +20x)+(y^2+ 12y) + 111 =0\\(x^2+20x+10^2-10^2)+(y^2+12y+6^2-6^2)+111=0\\(x+10)^2+(y+6)^2 -100-36+111=0\\(x+10)^2+(y+6)^2-25=0\\(x+10)^2+(y+6)^2=25\\(x+10)^2+(y+6)^2=5^2

Hence the equation in the given standard form is (x+10)^2+(y+6)^2=5^2

Learn more on equation of a circle here: brainly.com/question/1506955

4 0
2 years ago
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