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ivolga24 [154]
3 years ago
6

A car dealer sells four model types: A,B,C,D. On a given week, this dealer sold 10 cars of model A, 5 of model B, 8 of model C a

nd 3 of model D. The selling prices of each automobile are respectively $12,500, $11,800, $15,900 and $25,300.
Represent the data on the quantity sold using using matrix.
Mathematics
1 answer:
olasank [31]3 years ago
3 0

Answer:

its latter A

Step-by-step explanation:

i hope its help

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M(x) = 2.50x and the cost c(x) = 0.5x + 40
ololo11 [35]

Answer: It is c i just got it right

Step-by-step explanation:

3 0
3 years ago
A metal ring hole barrels together has a radius of 3 ft find the circumference and area
irina1246 [14]
Circumference = 2*pi*radius = 2*3.14*3 = 18.84 ft

Area = pi*radius^2 = 3.14*3*3= 28.26 ft^2
7 0
3 years ago
Find the x- and y- intercepts of parabola y=5x^2-16x+10
____ [38]

Y-INTERCEPT

y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

We need to use the quadratic formula

The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\

The x-intercepts are at:

(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)

5 0
2 years ago
Simplify the expression.<br> c^-6 d^4/c^-16 d^14
pochemuha

Answer:

\red{\frac{ {c}^{10}}{{d}^{10} } }

Step-by-step explanation:

\huge \: \frac{ {c}^{ - 6}  {d}^{4}}{ {c}^{ - 16}  {d}^{14} }  \\  \\  =  \huge \: \frac{ {c}^{16 - 6}}{{d}^{14 - 4} } \\  \\  =  \huge \:  \red{\frac{ {c}^{10}}{{d}^{10} } }

6 0
2 years ago
Answer this for me pleasee i need help
Fiesta28 [93]

Answer:

x = 5 and x = -3

Step-by-step explanation:

hope it helps

7 0
3 years ago
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