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DENIUS [597]
3 years ago
6

a box holds nine smaller boxes. each of the smaller boxes holds nine plastic containers. each plastic contai.er holds nine bags.

each bag holds nine elastic bands. how many ekastic bands are in the laregrst bix?
Mathematics
1 answer:
svp [43]3 years ago
4 0
So, basically ..you just multiply
9*9*9*9
6561
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Listed below are the measured radiation emissions​ (in W/kg) corresponding to cell​ phones: A,​ B, C,​ D, E,​ F, G,​ H, I,​ J, a
Sophie [7]

Answer: a. Mean = 0.696364

b. Median = 0.64

c. Midrange = 0.895

d. There is no Mode

e. 2. The maximun data value is the most relevant statistic, because it is closest to the limit of 1.6W/kg and that cell should be avoided.

Step-by-step explanation:

a) Mean is an average number of the data set, calculated by the sum of all the value divided by the quantity of the set:

mean = \frac{0.75+0.22+1.23+0.64+0.54+0.24+0.81+1.57+0.29+1.02+0.35}{11}

mean = 0.696364

b) Median is the middle number in the list of numbers. In this case, since there are 11 elements in the set, the middle number is:

sorted numbers of the data set:

0.22 0.24 0.29 0.35 0.54 0.64 0.75 0.81 1.02 1.23 1.57

median = 0.64

c) Midrange is another type of average number. It is calculated as:

midrange = \frac{high+low}{2}

midrange = \frac{1.57+0.22}{2}

midrange = 0.895

d) Mode is the number that appears most often in the list of numbers. For this data set, each number appears only one time, so there is no mode.

Mode = 0

e) According to the question, cell phone radiation is dangerous when it is higher than 1.6W/kg. The cell phone with the maximum data value (1.57 W/kg) should be avoided, since it is too close to the limit described.

So, the measures of center are not the most important statistic to be observed but the maximum data value.

7 0
3 years ago
Find the slope of the line through (0,5) and (5,5)
Fofino [41]

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the value of the next term of the sequence?
user100 [1]
Would it be (-3)^7? (-2187)
4 0
3 years ago
And, what is the least common multiple of 6,15, and 5
iren2701 [21]

Answer:

there is no multiplyer becuase 1 dosnt work no 2 nor3 nor4 nor5 nor6 and then you will be greater than 6 so it dosnt fit into 5 so

????/

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1. Chris takes 25 minutes to replace one car tyre.
vekshin1

Chris and Jim must replace a <em>total</em> quantity of 17 tyres.

<h3>What is the minimum number of tyres to be replaced?</h3>

In this problem we must use an inequality of the form f(x) ≥ a, where f(x) is the difference between the number of tyres replaced by Jim and the number of tyres replaced by Chris:

(25/20) · x - x ≥ 3

(5/20) · x ≥ 3

x ≥ 12

Then, the <em>minimum</em> number of tyres to be replaced is n = 15 + 12 = 17 tyres.  

To learn more on inequalities: brainly.com/question/20383699

#SPJ1

3 0
1 year ago
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