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3 years ago

I NEED HELP BEING TIMED

Mathematics

1 answer:

Paladinen [302]3 years ago

4 0

Answer:

Step-by-step explanation:

there are 4 cups in a quart. 4*5 1/2=22

22-4=18

ez pz ;)

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Find the variation constant and an equation of variation where y varies directly as x and y=16 when x=2

Jlenok [28]

Answer:

variation constant = k = 8

equation of variation : y = 8x

Step-by-step explanation:

Any relationship of variation can be written as y = kx

where k is the variation constant.

_______________________________________

Let the equationof relation between y and x be y =kx here as well

given

y = 16 when x = 2

substituting this value in the equation y = kx

16 = k*2

=> k = 16/2 = 8

Thus,

variation constant = k = 8

equation of variation : y = 8x

5 0

3 years ago

The pie below is cut into 6 equal slices. Show shade 2/3 of this pie.

Morgarella [4.7K]

Shade 4 slices out of the pie

5 0

3 years ago

Read 2 more answers

I need to solve this equasion. Could you please help me ?<img src="https://tex.z-dn.net/?f=y%20%3D%204%20x%5E%7B2%7D%20%2B3x%2B5

SOVA2 [1]

Hope I helped you. You didn't even asked any question.

3 0

3 years ago

A company estimates that it will sell ????(x) units of a product after spending x thousand dollars on advertising, as given by ?

zepelin [54]

Answer:

$(11\frac{1}{3},20)$

Step-by-step explanation:

If the Number of Sales of x units, N(x) is defined by the function:

$N(x)=-5x^3+235x^2-3400x+20000,10\leq x\leq 40$

$N'(x)=-15x^2+470x-3400\\When -15x^2+470x-3400=0\\x=20, x=11\frac{1}{3}$

Next, we text the critical points and the end points of the interval to see where the derivative is increasing.

$N'(10)=-200\\N'(11\frac{1}{3})=0\\N'(19)=115\\N'(20)=0\\N'(40)=-8600$

Thus, the rate of change of sales $N'(x)$ is increasing in the interval $(11\frac{1}{3},20)$ on 10≤x≤40.

7 0

3 years ago

Learning Task 4. Solve the problem by applying the sum and product of roots

Delvig [45]

Answer:

<em>Thus, the dimensions of the metal plate are 10 dm and 8 dm.</em>

Step-by-step explanation:

For a quadratic equation:

$x^2+bx+c=0$

The sum of the roots is -b and the product is c. Note the leading coefficient is 1.

We know the perimeter of the rectangular metal plate is 36 dm and its area is 80 dm^2. Being L and W its dimensions, then:

P=2(L+W)=36

A=L.W=80

Note both formulas are closely related to the roots of the quadratic equation, we only need to adjust the data for the perimeter to be exactly the sum of L+W and not double of it.

Thus we use the semi perimeter instead as P/2=L+W=18

The quadratic equation is, then:

$x^2-18x+80=0$

Factoring by finding two numbers that add up to 18 and have a product of 80:

$(x-10)(x-8)=0$

The solutions to the equation are:

x=10, x=8

Thus, the dimensions of the metal plate are 10 dm and 8 dm.

6 0

3 years ago