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MrRissso [65]
3 years ago
15

I could use some help with this question?

Mathematics
2 answers:
victus00 [196]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Area of the original one = 9 * 3 = 27 cm^2

Area of the scaled one = 18 * 6 = 108 cm^2

108 / 27 = 4

slega [8]3 years ago
3 0

Answer:

d

Step-by-step explanation:

if I divide the units of the scaled rectangle by the original you will get

18 \div 9 = 2 \\ 6 \div 3 = 2

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an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached.
nalin [4]

The total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²

Since an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached. The heights of the trapezoids and the apothem of the hexagon measure 2 centimeters each, and the length of the shorter base of each trapezoid is 1.5 centimeters, the radii of the hexagon, and the base of the trapezoid form a triangle of

  • height, h = apothem of the hexagon = 2 cm and
  • base, b = length of shorter base of trapezoid.
<h3>Area of the triangle</h3>

So, the area of this triangle is A = 1/2bh

= 1/2 × 1. 5 cm × 2 cm

= 1.5 cm × 1 cm

= 1.5 cm²

<h3>Area of the hexagon</h3>

Since there are 6 of such triangles in the hexagon, the area of the hexagon, A' = 6A

= 6 × 1.5 cm²

= 9.0 cm²

So, the total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²

Learn more about area of a hexagon here:

brainly.com/question/369332

5 0
2 years ago
Solve the system of equations.in this form: (x, y)<br><br> -5y + 8x = -18<br><br> 5y + 2x = 58
Gre4nikov [31]
If we add the equations it looks like
-5y + 8x + 5y + 2x = -18+58
so 10x=40
so x=40/10=4
now let's replace x by 4 in the second equation
5y +2*4=58
5y=58-2*4=58-8=50
so y=50/5=10
so (x, y) = (2, 10)
5 0
3 years ago
Read 2 more answers
Round the number 234,679 to the nearest hundred thousand
alexandr1967 [171]
To round numbers to the nearest hundred thousand, make the numbers whose last five digits are 00001 through 49999 into the next lower number that ends in 00000. For example 6,424,985 rounded to the nearest hundred thousand would be 6,400,000.
8 0
3 years ago
Read 2 more answers
A cube has a side length of 4 feet. What is the volume of the cube?
riadik2000 [5.3K]

Answer:

64 square ft^3

Step-by-step explanation:

If the side lengh is 3 then you would have 4^3 which is 64.

5 0
2 years ago
Read 2 more answers
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
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