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3 years ago

If the length of a rectangle is doubled, and its width is multiplied by 4, the area

Mathematics

1 answer:

agasfer [191]3 years ago

5 0

Answer:

The area would be multipled by 8

Step-by-step explanation:

Say you have a rectangle with the length of 5 and the width of 3, the area would be 15. Double the length, 10, and quadruple the width, 12. The area would be 120. 15 × 8 = 120.

Sorry if I'm wrong.

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3 years ago

Soni rent Anju a sum of Rs 40,000 at the rate of 2 paisa per 2 rupees per

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Answer:

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Step-by-step explanation:

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3 years ago

AB = BC, BC = CD, so AB = CD. Which property allows us to make this conclusion?

a_sh-v [17]

Answer:

Step-by-step explanation:

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3 years ago

You work for a company that produces custom picture frames. A new customer needs to frame a piece of rectangular artwork with di

miskamm [114]

Answer:

None of the choices are correct.

Step-by-step explanation:

Let x be the width of the frame,

The framed art cannot me more than 320 square inches

$(11 + 2x) \times (15+2x) \leq 320$

$(165 +30x +22x +4x^2 ) \leq 320$

$4x^2+52x + 165 \leq 320$

$4x^2 +52x + 165-320 \leq 0$

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By using the quadratic formula

$x = \frac{-b\pm \sqrt{(b^2-4ac)}}{2a}$

$x = \frac{-52\pm \sqrt{(52^2-4(4)(-155))}}{2(4)}$

$x = \frac{-52\pm \sqrt{(2704+2480)}}{2(4)}$

$x = \frac{-52\pm \sqrt{(5184)}}{2(4)}$

$x = \frac{-52\pm 72}{2(4)}$

$x = \frac{20}{8}$

$x= \frac{5}{2}$

$x = 2.5$

Frame must not be more than 2.5 inches wide.

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3 years ago