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UkoKoshka [18]
3 years ago
14

Cho số phức z thỏa mãn 2iz-5+i=i-(z-2i) tính modun của số phức w=z-1+i

Mathematics
1 answer:
ANEK [815]3 years ago
7 0

Solve the given equation for <em>z</em> :

2<em>iz</em> - 5 + <em>i</em> = <em>i</em> - (<em>z</em> - 2<em>i</em> )

2<em>iz</em> - 5 = 2<em>i</em> - <em>z</em>

(2<em>i</em> + 1) <em>z</em> = 2<em>i</em> + 5

<em>z</em> = (2<em>i</em> + 5)/(2<em>i</em> + 1)

<em>z</em> = (2<em>i</em> + 5)/(2<em>i</em> + 1) × (2<em>i</em> - 1)/(2<em>i</em> - 1)

<em>z</em> = (4<em>i</em> ² + 10<em>i</em> - 2<em>i</em> - 5) / (4<em>i</em> ² - 1)

<em>z</em> = (8<em>i</em> - 9)/(-5)

<em>z</em> = 9/5 - 8/5 <em>i</em>

<em />

Then

<em>w</em> = <em>z</em> - 1 + <em>i</em> = 4/5 - 3/5 <em>i</em>

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