The answer would be 55 because the sequence it`s going by is adding 2 to the number you`re adding up by. So for example, 5+6 =11, 11+8=19, 19+10= 29. and 29+12 == 41, so the next one would be 41+14=55. Does that makes sense?
Answer:
about 15 hours
Step-by-step explanation:
You want to find t such that N(t)=200. Fill in the equation with that information and solve for t.
200 = 400/(1 +399e^(-0.4t))
1 +399e^(-0.4t) = 400/200 = 2 . . . . . multiply by (1+399e^(-0.4t))/200
399e^(-0.4t) = 1 . . . . . . . . . . . . . . . . . . subtract 1
e^(-0.4t) = 1/399 . . . . . . . . . . . . . . . . . .divide by 399
-0.4t = ln(1/399) . . . . . . . take the natural log
t = ln(399)/0.4 ≈ 14.972 . . . . . . . divide by -0.4, simplify
Rounded to tenths, it will take 15.0 hours for half the people to have heard the rumor.
Answer:
-3 is the value of k in g(x)=kf(x)
Step-by-step explanation:
Both functions cross nicely at x=-3 so I'm going to plug in -3 for x:
g(x)=kf(x)
g(-3)=kf(-3)
To solve this for k we will need to find the values for both g(-3) and f(-3).
g(-3) means we want the y that corresponds to x=-3 on the curve/line of g.
g(-3)=-3
f(-3) means we want the y that corresponds to x=-3 on the curve/line of f.
f(-3)=1
So our equation becomes:
g(-3)=kf(-3)
-3=k(1)
-3=k
So k=-3.
Sixty-seven times a number, plus eight and nine tenths, is not greater than negative three hundred two
It the answer