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3 years ago

Legs and hypotenuse

Mathematics

1 answer:

zaharov [31]3 years ago

3 0

Answer:

Step-by-step explanation:

For a right triangle, the side that is opposite of the right angle is called the hypotenuse. This side will always be the longest side of the right triangle. The other two (shorter) sides are called legs.

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Logarithmic Functions <br> Can anyone help?

aliya0001 [1]

The equation $y\ =-2\log_{2}\left(x+2\right)+8$ has x Intercept at (14, 0) and Y intercept (0,6) and domain is (-2, ∞). Thus Option A,B and C are correct.

<h3>What are functions?</h3>

Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in set of y. x is independent variable while Y is dependent variable.

Given function,
= $y\ =-2\log_{2}\left(x+2\right)+8$
Domain of the above function is grater than -2 because at -2 system goes to infinity. Domain can be given as(-2, ∞).

Given function has x intercept at (14, 0) and y intercept at (0, 6).

Thus, the given function of log has following characteristic i.e.
x Intercept at (14, 0) and Y intercept (0,6) and domain is (-2, ∞).

Learn more about function here:

brainly.com/question/21145944

#SPJ1

6 0

2 years ago

Calculate the volume of a cylinder with height 14cm and diameter 10cm. Give your answer rounded to 3 SF.

USPshnik [31]

Un significant figured Volume=1099.56

3 sf = 1100.00

3 0

2 years ago

Read 2 more answers

Can you answere this please? i will give brainleyest

Mrrafil [7]

Answer:

alright

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So $\mu = 373, \sigma = 67$

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So $n = 5, s = \frac{67}{\sqrt{5}} = 29.96$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 373}{29.96}$

$Z = 1.23$

$Z = 1.23$ has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So $\mu = 526, \sigma = 107$