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Ray Of Light [21]
3 years ago
10

42. Calculate the value of c in the triangle below.

Mathematics
1 answer:
Verdich [7]3 years ago
5 0
A^2+b^2=c^2
9^2+40^2=c^2
81+1600=1681
Square it and u get 41
so c is 41
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Answer:

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Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -9 ,-8)

point B( x₂ , y₂ )≡ (-15 ,-16)

To Find:  

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Solution:

Slope of Line Segment AB is given as

Slope(AB)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }

Substituting the values we get

Slope(AB)=\dfrac{-16-(-8)}{-15-(-9)}\\\\Slope(AB)=\dfrac{-16+8}{-15+9}\\\\Slope(AB)=\dfrac{-8}{-6}=\dfrac{4}{3}

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Slope(AB)=\dfrac{4}{3}

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Step-by-step explanation:

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What is the value of p in the question below. 10x9/2x4= px 5
ycow [4]

Answer:

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Step-by-step explanation:

We have that:

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