In order to calculate the equivalent discount, consider the principle number is 100,
Then, 100 - 100 * 0.20 = 100 - 20 = 80
Now, 80 - 80 * 0.15 = 80 - 12 = 68
So, Total discount would be: 100 - 68 = 32%
Hope this helps!
Answer:
Yes
Step-by-step explanation:
It is false. Although integers above 0 divided by 0 is 0, negative numbers can also be integers (-1,-3,-10, etc.), and when they are divided by zero, they are undefined. That means that it is not really a number.
Answer:
(a). y'(1)=0 and y'(2) = 3
(b). 
(c). 
Step-by-step explanation:
(a). Let the curve is,
So the stationary point or the critical point of the differential function of a single real variable , f(x) is the value 
which lies in the domain of f where the derivative is 0.
Therefore, y'(1)=0
Also given that the derivative of the function y(t) is 3 at t = 2.
Therefore, y'(2) = 3.
(b).
Given function,
Differentiating the above equation with respect to x, we get
![y'(t)=\frac{d}{dt}[k \sin (bt^2)]\\ y'(t)=k\frac{d}{dt}[\sin (bt^2)]](https://tex.z-dn.net/?f=y%27%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Bk%20%5Csin%20%28bt%5E2%29%5D%5C%5C%20y%27%28t%29%3Dk%5Cfrac%7Bd%7D%7Bdt%7D%5B%5Csin%20%28bt%5E2%29%5D)
Applying chain rule,
![y'(t)=k \cos (bt^2)(\frac{d}{dt}[bt^2])\\ y'(t)=k\cos(bt^2)(b2t)\\ y'(t)= kb2t\cos(bt^2)](https://tex.z-dn.net/?f=y%27%28t%29%3Dk%20%5Ccos%20%28bt%5E2%29%28%5Cfrac%7Bd%7D%7Bdt%7D%5Bbt%5E2%5D%29%5C%5C%20y%27%28t%29%3Dk%5Ccos%28bt%5E2%29%28b2t%29%5C%5C%20y%27%28t%29%3D%20kb2t%5Ccos%28bt%5E2%29)
(c).
Finding the exact values of k and b.
As per the above parts in (a) and (b), the initial conditions are
y'(1) = 0 and y'(2) = 3
And the equations were
Now putting the initial conditions in the equation y'(1)=0
2kbcos(b) = 0
cos b = 0 (Since, k and b cannot be zero)
And
y'(2) = 3
![$\therefore kb2(2)\cos [b(2)^2]=3$](https://tex.z-dn.net/?f=%24%5Ctherefore%20kb2%282%29%5Ccos%20%5Bb%282%29%5E2%5D%3D3%24)
Answer:
The answer to your question is given below.
Step-by-step explanation:
Let the total number be U.
From the question given above, we were told that any number of B is 50% of the total number (i.e U).
Now, we shall determine the the total number (U) in terms of B.
50% of U = B
50/100 × U = B
50U / 100 = B
Cross multiply
50U = 100B
Divide both side by 50
U = 100B/50
U = 2B
Thus, the total number is 2B
Finally, we shall determine the answer to the question:
111 is 50% of ___
B = 111
Total number (U) = 2B
Total number (U) = 2 × 111
Total number (U) = 222
Therefore,
111 is 50% of 222
