AE is 9. ED is 6. The triangle ABE is proportional to ACD, so their sides are proportional. For example, AE:ED = AB:BC. So, ED/AE = 2/3 = BC/AB. This gives us 2/3 = x/10, which gives us x=6.6667

4 0

3 years ago

There are 376 students in 8th grade at Samuel's school. There are 47 8th graders trying out for football last Thursday. What per

statuscvo [17]

Answer:

87.5%

Step-by-step explanation:

There are 376 students in 8th grade at Samuel's school. There are 47 8th graders trying out for football last Thursday.

The number is students not trying out for football last Thursday is calculated as:

376 students - 47 students

= 329 students

The percent of 8th graders that did not try out for football is calculated as:

329 students/376 students × 100

= 329/376 × 100

= 87.5 %

8 0

2 years ago

Luis has 3 1/3 yards of ribbon to use for two separate presents, one of which is very large. If Luis uses 2 1/2 yards to decorat

never [62]

Answer:

$\frac{5}{6}$ yards

Step-by-step explanation:

Luis had $3\frac{1}{3}$ yards of ribbon in total to use for two presents. For the first present Luis used $2\frac{1}{2}$ yards of the ribbon.

Since she had $3\frac{1}{3}$ yards in total and she used $2\frac{1}{2}$ yards from it, the amount of ribbon left for second present can be obtained by taking out(subtracting) $2\frac{1}{2}$ yards from $3\frac{1}{3}$ .

So, the number of yards of ribbon left for second present will be:

$3\frac{1}{3}-2\frac{1}{2}\\\\ =\frac{10}{3}-\frac{5}{2}\\\\ =\frac{10(2)-5(3)}{2 \times 3}\\\\ =\frac{20-15}{6}\\\\ =\frac{5}{6}$

This means Luis had $\frac{5}{6}$ yards of ribbon for the second present.

5 0

3 years ago