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2 years ago

How to solve this problem

Mathematics

1 answer:

mart [117]2 years ago

7 0

Simply make a proportion. x is the long side for the small triangle and 4 is the short side. x is the short side of the medium triangle and 9 is the long side. Your proportion should look like this x/4=9/x. The cross multiply to get x squared = 36 . x=6 You can also draw a grid if you were taught to do so in school.

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I cant see the answer what is it

JulsSmile [24]

Whats the question??????????????????????

8 0

3 years ago

Read 2 more answers

PLEASE HELP! Find the distance between each pair of points. Round your answers to the nearest tenth.

strojnjashka [21]

A.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \left( -5 \right) \right)^2 + \left( -2 - \left( -3 \right) \right)^2} \\ \\ = \sqrt{ 1 + 1} \\ \\ = \sqrt{ 2 }$

b.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \frac{ 7 }{ 2 } \right)^2 + \left( \frac{ 5 }{ 2 } - 1 \right)^2} \\ \\= \sqrt{ \frac{ 225 }{ 4 } + \frac{ 9 }{ 4 }} \\ \\= 3 \frac{\sqrt{ 26 }}{ 2 }$

6 0

3 years ago

G verify that the divergence theorem is true for the vector field f on the region

Alenkasestr [34]

$\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1$

Converting to spherical coordinates, we have

$\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi$

On the other hand, we can parameterize the boundary of $E$ by

$\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle$

with $0\le u\le2\pi$ and $0\le v\le\pi$ . Now, consider the surface element

$\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv$
$\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv$
$\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv$

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

$\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv$
$=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi$

as required.

3 0

3 years ago

on monday mrs jones spent 32 dollars on 4 books. on tuesday she spent $16 on more books.each book cost the same amount. how many

Gala2k [10]

She bought 6 books in all because if you divide the whole number of all the books in all which is $32 divide that by 4 so..

32 ÷4=8

so thats just the 4 books then she buys 16 more dollars worth that which you then multiply 4 times 8 which give you 16 so you then add the 4 books to the other 2 books spent on the next day

ANSWER: 6 BOOKS IN ALL

6 0

2 years ago

kogti [31]

Answer:

B is correct. Your starting amount is 210$ And you're taking away 15$ each time she uses the club,x.

Step-by-step explanation:

Answer:

The linear function model the situation is b = 210 - 15x .

Option (B) is correct .

Step-by-step explanation:

Let us assume that the number of times giselle uses the club be x .

As given

giselle pays $210 in advance on her account at the athletic club.

Each time she uses the club,$15 is deducted from the account.

Let suppose that the money left after giselle uses the club x times is b .

Than the equation becomes

Money left = Amount pay in advance - Deducted amount × Number of times giselle uses the club .

Put all the values in the above

b = 210 - 15 × x

b = 210 - 15x

Therefore the linear function model the situation is b = 210 - 15x .

Option (B) is correct .

7 0

2 years ago