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Zepler [3.9K]
3 years ago
7

Altogether, Tim, Laura, and Eric worked 210 hours campaigning for their friend Jake who was running for the senate. Laura worked

10 hours more then Tim, and Eric worked twice as many hours as Laura. How many hours did Laura work on the campaign?​
Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0

Let \:  x  \: be  \: the  \: time  \: which \:  Laura \:  worked \\  The \:  time  \: Tim  \: worked:x - 10 \\ The  \: time \:  Eric \:  worked:2x \\ We \:  have  \: an \:  equation:x + x - 10 + 2x = 210 \\  <   =  > 4x = 220 \\  <  =  > x = 55 \: (hrs) \\ So \:  Laura  \: worked  \: for  \: 55 \:  hours  \: on \:  the  \: campaign.

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Find the missing side of each triangle. Leave your answers in simplest radical form.
jeka57 [31]

Answer:

x = 2\sqrt{34}

Step-by-step explanation:

Using Pythagoras identity in the right triangle

x² = 10² + 6² = 100 + 36 = 136 ( take the square root of both sides )

x = \sqrt{136} = \sqrt{4(34)} = 2\sqrt{34}

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2 years ago
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deff fn [24]

Answer:

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Step-by-step explanation:

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2 years ago
Solve the equation sine Ф=0.6792 for 0°≤Ф≤360
Sergio [31]

Answer:

42.78⁹, 137.22⁹.

Step-by-step explanation:

sine Ф=0.6792

Angle Ф in the first quadrant = 42.78 degrees.

The sine is also positive in the second quadrant so the second solutio is

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3 years ago
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Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
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3 0
3 years ago
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Step-by-step explanation:

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HL (hypotenuse,leg)

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