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kari74 [83]
4 years ago
10

For mr. fujimoto's class, there are 7 possible assignments. however, students only have to choose 5 assignments to complete and

submit. if the order in which the students submit the assignments doesn't matter, how many different combinations of 5 are there?
Mathematics
1 answer:
iren2701 [21]4 years ago
5 0
We know that

The formula for combinations is<span>
C=n!/[(n-r)!*r!]
where
n is the total number of objects you choose from
r is the number that you choose to arrange

in this problem
n=7 </span>assignments

r=5 assignments

<span> C=7!/[(7-5)!*5!]-----> C=7!/[2!*5!]---> (7*6*5!)/(2*5!)-----> C=21</span>

<span>
the answer is</span>

<span>21</span>

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KATRIN_1 [288]

Answer:

0.9544 = 95.44% probability that the sample mean time for reading comic books per week is between 5 and 7 hours.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 6, \sigma = 2, n = 16, s = \frac{2}{\sqrt{16}} = 0.5

What is the probability that the sample mean time for reading comic books per week is between 5 and 7 hours

This is the pvalue of Z when X = 7 subtracted by the pvalue of Z when X = 5. So

X = 7

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{7 - 6}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 5

Z = \frac{X - \mu}{s}

Z = \frac{5 - 6}{0.5}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean time for reading comic books per week is between 5 and 7 hours.

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