Answer:
Area of the shaded region = 6.88 cm²
Step-by-step explanation:
Area of the shaded region = Area of the rectangle - Area of the semicircle
Area of the rectangle = Length × Width
Length of the rectangle = AD = 8 cm
Width of the rectangle = OP = 4 cm [OP, OB and OC are the radii of the circle which are equal in measures]
Area of the rectangle = 8 × 4 = 32 cm²
Area of the semicircle = 
= 
= 
= 25.12 cm²
Area of the shaded region = 32 - 25.12
= 6.88 cm²
Answer:
14+=+2L+%2B+2%28L-3%29 Simplify and solve for L
14+=+2L+%2B+2L+-+6 Combine like-terms.
14+=+4L-6 Add 6 to both sides.
20+=+4L Divide both sides by 4.
5+=+L The length is 5 meters.
W+=+L-3
W+=+5-3
W+=+2meters.
The width is 2 meters.
P+=+2L%2B2W
P+=+2%285%29%2B2%282%29
P+=+10%2B4
P+=+14meters.
Step-by-step explanation:
A = P + I
2a = a + PTR/100
2a = a + 5aT/100
2a = a(1+T/20)
2=1+T/20
T=20 yrs
P(at least 5 rolls until 1) = P(4 rolls are not 1) = 5/6 x 5/6 x 5/6 x 5/6 = 0.4823 (4sf)
Fewer than 7 rolls to get second 1 after first takes 3 rolls means second occurs on 4th, 5th or 6th roll
The probability of each of these is 1/6, 5/6 x 1/6 and 5/6 x 5/6 x 1/6 respectively.
P(second 1 on 4th, 5th or 6th roll) = 1/6 + 5/36 + 25/216 = 91/216 = 0.4213 (4sf)
