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madreJ [45]
3 years ago
6

Look at the figure below; what additional information do you need to have to determine if segment DE is the midsegment?

Mathematics
1 answer:
77julia77 [94]3 years ago
3 0
1. If you knew that DE = \frac{1}{2}CB
Then you would know it is a mid-segment.

2. If you knew that CD =  DA and BE = EA  (point D and point E are midpoints of their respective segments)

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3. Liam has a rectangular back
MA_775_DIABLO [31]

Answer:

Length of the other side of the backyard is 80.4 feet.

Step-by-step explanation:

Let the dimensions of the Liam's rectangular backyard = 85 feet × a feet

Diagonal of the rectangle, AD = 117 feet

When we apply Pythagoras theorem in ΔABD,

AD² = AB² + BD²

(117)² = (85)² + BD²

a² = 13689 - 7225

a = √6464

  = 80.399 feet

a ≈ 80.4 feet

Therefore, length of the other side of the backyard is 80.4 feet.

3 0
3 years ago
How many solutions does the following system have? <br><br> 2x+3y=1; -3x-2y=-1
zysi [14]

Answer:

x = 1/5 , y = 1/5

Step-by-step explanation:

Solve the following system:

{2 x + 3 y = 1 | (equation 1)

-3 x - 2 y = -1 | (equation 2)

Swap equation 1 with equation 2:

{-(3 x) - 2 y = -1 | (equation 1)

2 x + 3 y = 1 | (equation 2)

Add 2/3 × (equation 1) to equation 2:

{-(3 x) - 2 y = -1 | (equation 1)

0 x+(5 y)/3 = 1/3 | (equation 2)

Multiply equation 1 by -1:

{3 x + 2 y = 1 | (equation 1)

0 x+(5 y)/3 = 1/3 | (equation 2)

Multiply equation 2 by 3:

{3 x + 2 y = 1 | (equation 1)

0 x+5 y = 1 | (equation 2)

Divide equation 2 by 5:

{3 x + 2 y = 1 | (equation 1)

0 x+y = 1/5 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x+0 y = 3/5 | (equation 1)

0 x+y = 1/5 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 1/5 | (equation 1)

0 x+y = 1/5 | (equation 2)

Collect results:

Answer: {x = 1/5 , y = 1/5

8 0
3 years ago
Evaluate the following expression:<br> - (2.3)² – 52
zalisa [80]

Answer:

-57.29

Step-by-step explanation:

5 0
3 years ago
Calculate the derivative of the following function. y=e6x(6x+1)5
netineya [11]

Answer:

Y' = 360ex+ 30e

Step-by-step explanation:

Y=e×6x×(6x+1) × 5

y'= d/dx (e×6x ×(6x+1)×5)

y'=d/dx(30ex ×(6x+1))

y'=d/dx(180ex^2 + 30ex)

y'=d/dx(180ex^2) + d/dx (30ex)

Calculate the derivative

y'=180e×2x +30e

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6 0
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From 1000 students half being boys and half being girls 100 names were pulled out of a hat to complete a survey for school what
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Random sampling. its where you pick or make a smaple at random
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3 years ago
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