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Ksenya-84 [330]
3 years ago
15

A group of 30 students were asked about their favorite way to eat eggs.

Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

It's too short. Write at least 20 characters to explain it well.

Your answer can't be empty

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Can we get a picture please
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a minor league baseball team plays 114 games in a season. if the team won 14 more than three times as many games as they lost, h
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They will have played with 19 loses 76 wins ! 
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3 years ago
The area of a triangle is 45.5 cm2 and the base is 10 cm.
blondinia [14]
The area of a triangle is A=1/2b*h
You have the base (b) and you have the area (A)
So, if you plug in what you know, you get this:
45.5=1/2*10*h
Simplify it:
45.5=5h

Now solve for h
Divide by 5 to get h alone:
9.1=h

Your height is 9.1cm
Hope this helps :)
3 0
3 years ago
Read 2 more answers
I need the answer ASAP
3241004551 [841]

Answer:

Hey there!

The answer is 2 1/4, which is 2.25

Let me know if you have any other questions!

5 0
3 years ago
Read 2 more answers
Please help with imaginary numbers worksheet!
mihalych1998 [28]

Problem 5

<h3>Answer:   6i</h3>

------------------

Explanation:

We have these four identities

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

=============================================

Problem 6

<h3>Answer:  -3i</h3>

------------------

Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\

=============================================

Problem 7

<h3>Answer:   -1</h3>

------------------

Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1

=============================================

Problem 8

<h3>Answer:    -1 + i</h3>

------------------

Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i

8 0
2 years ago
Read 2 more answers
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