X=7, y=6. that’s your answer!
Answer:
6 km
Step-by-step explanation:
You use Pythagoras
![{QN}^2 = (PN)^{2}+(PQ)^{2} \\PQ = \sqrt{(QN)^{2}-(PN)^{2} }\\ PQ = 6 km](https://tex.z-dn.net/?f=%7BQN%7D%5E2%20%3D%20%28PN%29%5E%7B2%7D%2B%28PQ%29%5E%7B2%7D%20%5C%5CPQ%20%3D%20%5Csqrt%7B%28QN%29%5E%7B2%7D-%28PN%29%5E%7B2%7D%20%20%7D%5C%5C%20PQ%20%3D%206%20km)
Answer: 1527
Step-by-step explanation:
Total Area = 7500 ft^2
Area covered by one student = Area of one circle
= π*r^2
r = radius of circle = 2.5/2 = 1.25 ft
Area covered by one student = π*1.25^2 = 4.91 ft^2
Number of students who can fit into total area = Total Area/Area covered by one student
Number of students who can fit into total area = 7500/4.91 = 1527.49
Hence the answer is 1527 students
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
8/8 is bigger than 3/4 because 8/8 is equivalent to 1 and 1 is bigger than 3/4.