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Natalka [10]
2 years ago
15

URGENT HELP NEEDED dawg ITS DUE IN 5 MIN can someone help with deal 2? A pizza restaurant offers the following deals. Deal #1 $8

.99 for one large pizza and $5 for each additional large pizza on the same order. Deal#2 $6.00 per large pizza. whats the equation?​
Mathematics
1 answer:
WARRIOR [948]2 years ago
6 0

Answer: Deal one: y = 8.99x + 5 Deal two: y = 6

Step-by-step explanation: I'm not quite sure how you want the equation, but I hope this helps.

You might be interested in
Which is the solution to the inequality?<br> y + 15 less-than 3
Arte-miy333 [17]

Hey there!

"less than" is "<"

y+15<3

Solve it:

y<3-15

y<-12

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

6 0
1 year ago
Solve the equation: 5x + 5 = 0
Igoryamba

Answer:

x = -1

Step-by-step explanation:

5x + 5 = 0

Subtract 5 from each side

5x+5-5 = 0-5

5x = -5

Divide by 5 on each side

5x/5 = -5/5

x = -1

3 0
2 years ago
Read 2 more answers
Which best describes the graphs of the line that passes through (−12, 15) and (4, −5), and the line that passes through (−8, −9)
konstantin123 [22]

Answer:

C) They are perpendicular lines.

Step-by-step explanation:

We first need to find the slope of the graph of the lines passing through these points using:

m =  \frac{y_2-y_1}{x_2-x_1}

The slope of the line that passes through (−12, 15) and (4, −5) is

m_{1} =  \frac{ - 5 - 15}{4 -  - 12}

m_{1} =  \frac{ - 20}{16}  =  -  \frac{5}{4}

The slope of the line going through (−8, −9) and (16, 21) is

m_{2} =  \frac{21 -  - 9}{16 -  - 8}

m_{2} =  \frac{21  + 9}{16  + 8}

m_{2} =  \frac{30}{24}  =  \frac{5}{4}

The product of the two slopes is

m_{1} \times m_{2} =  -  \frac{4}{5}  \times  \frac{5}{4}  =  - 1

Since

m_{1} \times m_{2} =  - 1

the two lines are perpendicular.

4 0
3 years ago
Read 2 more answers
PLEASE HELP WILL MARK BRAINLIEST
Romashka [77]

Answer:

A.The mean would increase.

Step-by-step explanation:

Outliers are numerical values in a data set that are very different from the other values. These values are either too large or too small compared to the others.

Presence of outliers effect the measures of central tendency.

The measures of central tendency are mean, median and mode.

The mean of a data set is a a single numerical value that describes the data set. The median is a numerical values that is the mid-value of the data set. The mode of a data set is the value with the highest frequency.

Effect of outliers on mean, median and mode:

  • Mean: If the outlier is a very large value then the mean of the data increases and if it is a small value then the mean decreases.
  • Median: The presence of outliers in a data set has a very mild effect on the median of the data.
  • Mode: The presence of outliers does not have any effect on the mode.

The mean of the test scores without the outlier is:

   \bar{x}=\frac{Total of the observations-Outlier value}{n-1} \\=\frac{(86*16)-72}{15} \\=\frac{1304}{15}\\ =86.9333

*Here <em>n</em> is the number of observations.

So, with the outlier the mean is 86 and without the outlier the mean is 86.9333.

The mean increased.

Since the median cannot be computed without the actual data, no conclusion can be drawn about the median.

Conclusion:

After removing the outlier value of 72 the mean of the test scores increased from 86 to 86.9333.

Thus, the the truer statement will be that when the outlier is removed the mean of the data set increases.

4 0
2 years ago
Does anyone know how to do this?
eduard

Answer:

on 60!! Hope this help's

Step-by-step explanation:

6 0
2 years ago
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