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damaskus [11]
3 years ago
5

How many ml in 0.006​

Mathematics
2 answers:
timama [110]3 years ago
7 0

Answer:

6ml

Step-by-step explanation:

san4es73 [151]3 years ago
6 0

Answer:

if 0.006 l= 6ml

Step-by-step explanation:

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2( 1/5 m− 2/5 )+ 3/5
Liula [17]

Answer:

2m/5-1/5

Step-by-step explanation:

2*m-2/5+3/5

2(m-2)/5+3/5

2(m-2)/5+3/5

2m-4/5+3/5

2m/5-1/5

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3 years ago
64 as a mixed number
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3 years ago
What is the period of a wave if the wavelength is 100 m and the speed is 200 m/s?
Iteru [2.4K]
It is A because I did 100 times 200 and I got 200,000
5 0
3 years ago
Read 2 more answers
Volume and Surface Area<br><br> Math help 100 points
kondor19780726 [428]
Part 1) we have that
volume smaller solid=512 cm³
volume larger solid=2197 cm³

we know that
volume larger solid=[scale factor]³*volume smaller solid
scale factor=∛[volume larger solid/volume smaller solid]
scale factor=∛[2197/512]-----> scale factor=1.625


Part 2) 
the ratio of the surface areas is equal to [scale factor]²
1.625²-------> 2.64

Part 3)
surface area smaller solid=960 cm²
then
surface area larger solid=scale factor²*surface area smaller solid
surface area larger solid=[1.625]²*960-----> 2535 cm²
 surface area larger solid is  2535 cm²


3 0
3 years ago
Read 2 more answers
A​ hot-air balloon is 140 ft140 ft above the ground when a motorcycle​ (traveling in a straight line on a horizontal​ road) pass
luda_lava [24]

Answer:

Step-by-step explanation:

Given

Balloon velocity is 14 ft/s upwards  

Distance between balloon and cyclist is 140 ft

Velocity of motor cycle is 88 ft/s

After 10 sec  

motorcyclist traveled a distance of d_c=88\times 10=880 ft

Distance traveled by balloon in 10 s

d_b=14\times 10=140 ft

net height of balloon from ground =140+140=280 ft[/tex]

at t=10 s

distance between cyclist and balloon is z=\sqrt{280^2+880^2}

z=923.47 ft

now suppose at any time t motorcyclist cover a distance of x m and balloon is at a height of h m

thus z^2=(88t)^2+(14t+140)^2

differentiating w.r.t time

\Rightarrow z\frac{\mathrm{d} z}{\mathrm{d} t}=14\cdot \left ( 14t+140\right )+88\cdot \left ( 88t\right )

\Rightarrow at\ t=10 s

\Rightarrow \frac{\mathrm{d} z}{\mathrm{d} t}=\frac{14\cdot \left ( 14t+140\right )+88\cdot \left ( 88t\right )}{z}

\Rightarrow \frac{\mathrm{d} z}{\mathrm{d} t}=\frac{14\times 280+88^2\times 10}{923.471}

\Rightarrow \frac{\mathrm{d} z}{\mathrm{d} t}=\frac{81,360}{923.471}=88.102\ ft/s

3 0
3 years ago
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