Answer:
The amplitude of the absorbed mass can be found
for ka:
now
![w^2=\frac{K_{a} }{m_{a} } \\m_{a} =\frac{K_{a} }{w^2} =\frac{125000}{[6000*2\pi /60]^2} =0.317kg](https://tex.z-dn.net/?f=w%5E2%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bm_%7Ba%7D%20%7D%20%5C%5Cm_%7Ba%7D%20%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bw%5E2%7D%20%3D%5Cfrac%7B125000%7D%7B%5B6000%2A2%5Cpi%20%2F60%5D%5E2%7D%20%3D0.317kg)
Answer:
8861.75 m approximately 8862 m
Explanation:
We need to remember Newton's 2nd Law which says that the force experienced by an object is proportional to his acceleration and that the constant of proportionality between those two vectors correspond to the mass of the object.
for the weight of an object (which is a force) we have that the acceleration experienced by that object is equal to the gravitational acceleration, obtaining that 
For simplicity we work with 
despiting the effect of the height above sea level. In this problem, we've been asked by the height above sea level that makes the weight of an object 0.30% more lighter.
In accord with the formula 
the "normal" or "standard" weight of an object is given by 
when 
, so we need to find the value of 
that makes 
meaning that the original weight decrease by a 0.30%, so now we operate...
now we group like terms on the same sides 
we cancel equal tems on both sides and obtain that 
Answer: A) Product identifier
Explanation:
A product identifier is a means, name or number used to identify hazardous and dangerous chemicals on a label or in the SDS( safety data sheet). It provides a special means which helps the user to identify the chemical. Any product identifier used should permit a cross-references to be made among the listed hazardous chemicals required in the written hazard communication program, and the label including SDS(safety data sheet).
