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3 years ago

Which of the following placards allows a driver to park in a handicapped parking space.

Engineering

2 answers:

malfutka [58]3 years ago

4 0

All of the above ......

KATRIN_1 [288]3 years ago

4 0

All hope it helps :)

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You are given a body with no body forces and told that the stress state is given as: ⎡ ⎣ 3αx 5βx2 + αy γz3 5βx2 + αy βx2 0 γz3 0

Lady bird [3.3K]

Answer:

This doesn't represent an equilibrium state of stress

Explanation:

∝ = 1 , β = 1 , y = 1

x = 0 , y = 0 , z = 0 ( body forces given as 0 )

Attached is the detailed solution is and also the conditions for equilibrium

for a stress state to be equilibrium all three conditions has to meet the equilibrum condition as explained in the attached solution

5 0

3 years ago

A 5cm diameter copper sphere (of density = 8954 kg/m3, specific heat capacity = 0.3831 kJ/kg K) is initially at a uniform temper

Korolek [52]

Answer:

Temperature inside sphere after 10 minutes = 19924.33K

Explanation:

Detailed explanation and calculation is shown in the image below

6 0

3 years ago

What are some constraints related to size, time, or materials? Remember, constraints are limitations, issues, or obstacles.

Sergeeva-Olga [200]

Answer:

too big, too small, deadlines, not enough materials

Explanation:

4 0

3 years ago

A ramp from an expressway with a design speed of 30 mi/h connects with a local road, forming a T intersection. An additional lan

hram777 [196]

Answer:

the width of the turning roadway = 15 ft

Explanation:

Given that:

A ramp from an expressway with a design speed(u) = 30 mi/h connects with a local road

Using 0.08 for superelevation(e)

The minimum radius of the curve on the road can be determined by using the expression:

$R = \dfrac{u^2}{15(e+f_s)}$

where;

R= radius

$f_s$ = coefficient of friction

From the tables of coefficient of friction for a design speed at 30 mi/h ;

$f_s$ = 0.20

So;

$R = \dfrac{30^2}{15(0.08+0.20)}$

$R = \dfrac{900}{15(0.28)}$

$R = \dfrac{900}{4.2}$

R = 214.29 ft

R ≅ 215 ft

However; given that :

The turning roadway has stabilized shoulders on both sides and will provide for a onelane, one-way operation with no provision for passing a stalled vehicle.

From the tables of "Design widths of pavement for turning roads"

For a One-way operation with no provision for passing a stalled vehicle; this criteria falls under Case 1 operation

Similarly; we are told that the design vehicle is a single-unit truck; so therefore , it falls under traffic condition B.

As such in Case 1 operation that falls under traffic condition B in accordance with the Design widths of pavement for turning roads;

If the radius = 215 ft; the value for the width of the turning roadway for this conditions = 15ft

Hence; the width of the turning roadway = 15 ft

5 0

3 years ago

A spherical tank is being designed to hold 10 moles of carbon dioxide gas at an absolute pressure of 5 bar and a temperature of

lesya692 [45]

Answer:

r=0.228m

Explanation:

The equation that defines the states of a gas according to its thermodynamic properties is given by the general equation of ideal gases

PV=nRT

where

P=pressure =5bar=500.000Pa

V=volume

n=moles=10

R = universal constant for ideal gases = 8.31J / (K.mol)

T=temperature=80F=299.8K

solvig For V

V=(nRT)/P

$V=(\frac{(10)(8.31)(299.8)}{500000} )\\V=0.0498m^3$

we know that the volume of a sphere is

$V=\frac{4\pi r^3}{3} \\$

solving for r

$r=\sqrt[3]{ \frac{3 V}{4\pi } }$

solving

$r=\sqrt[3]{ \frac{3 (0.049)}{4\pi } }\\r=0.228m$

4 0

3 years ago