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olganol [36]
3 years ago
9

There are two questions about SolidWorks.

Engineering
1 answer:
Nataliya [291]3 years ago
4 0

Answer:

1. It is a good practice to fully define a sketch to avoid having erroneous dimensions on the faces of a solid, this avoids that when it is required to make an assembly with the drawn part appear assembly errors.

2. The 2D sketch should always be done on a plane, so solidworks would ask you to select a plane on which you want to make the sketch, on the other hand, if it is a 3D sketch, solidworks allows you to do it without the need for Select any plane.

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1 import java.util.Scanner; 3 public class EqualityAndRelational { 4 public static void main (String args) args) { int userBonus
Anastaziya [24]

Missing Part of the Question

Complete the expression so that userPoints is assigned with 0 if userBonus is greater than 20 (second branch). Otherwise, userPoints is assigned with 10 (first branch

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

( Your solution goes here)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

Answer;

Replace

( Your solution goes here)

With

if(userBonus>20).

The full program becomes

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

if(userBonus>20)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

7 0
3 years ago
Given an unsorted array of distinct positive integers A[1..n] in the range between 1 and 10000 and an integer i in the same rang
AnnZ [28]

Answer:

Explanation:

Arbitrary means That no restrictions where placed on the number rather still each number is finite and has finite length. For the answer to the question--

Find(A,n,i)

for j =0 to 10000 do

frequency[j]=0

for j=1 to n do

frequency[A[j]]= frequency[A[j]]+1

for j =1 to n do

if i>=A[j] then

if (i-A[j])!=A[j] and frequency[i-A[j]]>0 then

return true

else if (i-A[j])==A[j] and frequency[j-A[j]]>1 then

return true

else

if (A[j]-i)!=A[j] and frequency[A[j]-i]>0 then

return true

else if (A[j]-i)==A[j] and frequency[A[j]-i]>1 then

return true

return false

7 0
3 years ago
Answer: D because you need an explanation <br> Explanation: Please I'll mark Brainliest
mylen [45]

Answer:Could you give a picture or something so I could answer.

Explanation:

6 0
3 years ago
A plant of order 50 is to track steps and sinusoids of frequency ω = 1 rad/sec. Write down the form of the pole placement contro
adelina 88 [10]

Answer:

The term for the pole placement controller is G/(s²  + 1) +GH

Explanation:

Solution

Given that:

A plant of order = 50

The sinusoids of frequency ω = 1 rad/sec.

Lt the transfer of equation of plant be represented as follows:

T/F = G/1+GH

= K/ans^50 + ans - 1^49 +........As +a₀

The pole placement order becomes:

Step 1:

Gc (s) =A/s

Now

The transfer function = GGc/1 +GG c H

=G/s + GHA

Step 2:

For sinusoidal controller w = = 1 rad/sec.

Gc (s) = w/s² + w²

= 1 + /s²  + 1

Thus

The transfer function = GGc/1 +GGcH

= G/(s²  + 1) +GH

the term for the pole placement controller is G/(s²  + 1) +GH

6 0
3 years ago
Which ranks careers in the Architecture and Construction career cluster based on the typical number of years for each degree, go
timama [110]

Answer:

hmm tdyufrjhfjjbdjjkljgjjddtu

8 0
3 years ago
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