Answer:
D
O
N
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KNOW
Step-by-step explanation:
Y
O
U ARE
W
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L
C
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Answer:
The answer is below
Step-by-step explanation:
Let us assume the rate of printing in machine A is x per hour and the rate for machine B is y. Given that machine B prints at half the rate of machine A, therefore:
y = (1/2)x (1)
Also, both machine produces 200 newspaper printouts, and both operate at different times for a total of 4 hours. Therefore:
200/x + 200/y = 4 (2)
Put y = (1/2)x in equation:

Put x = 150 in equation y:
y=(1/2)150 = 75
Therefore the rate of machine A is 150 newspapers per hour while that of machine B is 75 newspapers per hour
The answer is 3 divided by 1/2
This is easy to do because you can factor
example
6/2=3 because 6=2*3 so 6/2=3/1 times 2/2 or 3
2x^3+17x^2+23x-42 can be factored out to equal
(x-1)(x+6)(2x+7)
so [(x-1)(x+6)(2x+7)]/(2x+7)=[(x-1)(x+6)] times (2x+7)/(2x+7)=(x-1)(x+6)=x^2+5x-6
the answer is (x-1)(x+6) or x^2+5x-6