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emmasim [6.3K]
3 years ago
8

4 — = 16 M Omg help me this is due tomorrow!!!

Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0

Step-by-step explanation:

4/m=16

4/m=16/1

16m=4

divide both sides by 16

therefore, m is equal to 0.25

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I need help with letter D
Ivahew [28]
To find 1. all you have to do is 165/30 and you get $5.50. To find 2. you have to add 165+45 you get 210. then divide 210/40 and you get 5.25
4 0
3 years ago
Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a^2 – 18 square units. Which i
netineya [11]

we know that

The area of the hexagon is equal to the sum of the areas of the six equilateral triangles

Let

x-------> area of one equilateral triangle

so

6x=24a^{2} -18

Divide by 6 both sides

x=4a^{2} -3 -------> area of one equilateral triangle

To find an equivalent expression for the area of the hexagon based on the area of a triangle, multiply the area of one equilateral triangle by 6

6*(4a^{2} -3)

therefore

the answer is

The equivalent expression is equal to 6*(4a^{2} -3)

6 0
3 years ago
Read 2 more answers
What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then 
y + 1 = 0
y = -1
so x - y = 6
     x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".

4 0
3 years ago
Read 2 more answers
Select the correct answer.
san4es73 [151]

Answer:

B

Step-by-step explanation:

Is the answer

6 0
3 years ago
Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50
steposvetlana [31]

<u>Answer-</u>

f(2)= 6x^4-10x^3+40x-50=46

<u>Solution-</u>

The given function is,

\Rightarrow f(x)= 6x^4-10x^3+40x-50

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50

\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50

\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50

\Rightarrow f(2)= 96-80+80-50

\Rightarrow f(2)= 96-50

\Rightarrow f(2)= 46

Therefore, f(2) was found to be 46.


7 0
3 years ago
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