Question

In ΔXYZ, x = 71 cm, y = 91 cm and z=71 cm. Find the area of ΔXYZ to the nearest square centimeter.

Answer 1

since its an isoscelies trangle, they probably wanted you to do base times height

make a 71-91/2-x x triangle

where x is the height of the triangle to the base 91 and 71 is the hypothenuse

and then do bh/2

or

use heron's formula

s= 71+91/2

area= $\sqrt{(71+91/2)(71+91/2-71)(71+91/2-71)(71+91/2-91)}$

have fun solving that