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3 years ago

A computer is performing a binary search on the sorted list of 7 numbers below.

Computers and Technology

2 answers:

suter [353]3 years ago

6 0

Answer:

The answer is "Option D".

Explanation:

Binary search is also an efficient mechanism for only a sorted item list. It separates the element into one half of the checklist repeatedly, till you have narrowed it down to the only single place.

In this search, the number of comparisons is much more efficient than in the series to use the binary search approach, the items also should be shown, that's why the last choice is correct.

zhenek [66]3 years ago

6 0

Answer:

Explanation:

Binary search will start in the middle of the list, find which side the value is at, then look at the middle of those values. This is incredibly efficient for larger values (Although it needs to be sorted) and practical in many instances. Let's say that the desired number is 1, the binary search would look at "50" first, then proceed to compare with "5" and finally on it's third iteration, pick 1.

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1.Know the BMI of the user. First, the user will input the height in meters and weight in kilograms. After inputting, the inputt

Verizon [17]

The program that checks the BMI of a patient is given below:

#include <iomanip>

#include <iostream>

#include <math.h>

using namespace std;

// C++ program to illustrate

// how to calculate BMI

float BMI(float height, float weight)

{

float bmi = weight / pow(height, 2);

return bmi;

}

int main()

{

float height = 1.79832;

float weight = 70;

// Function call

float bmi = BMI(height, weight);

cout << "The BMI is " << setprecision(15) << bmi

<< " so ";

// Conditions to find out BMI category

if (bmi < 18.5)

cout << "underweight";

else if (bmi >= 18.5 && bmi < 24.9)

cout << "Healthy";

else if (bmi >= 24.9 && bmi < 30)

cout << "overweight";

else if (bmi >= 30)

cout << "Suffering from Obesity";

return 0;

}

// This code is contributed by aarohirai2616.

<h3>Output: </h3>

The BMI is 21.64532402096181 so Healthy