(i) Share 350m in the ratio 3:7

2. a. The center for research in data science has a vacancy of 5 interns under a research attachment program. However, 20 studen

Yuliya22 [10]

Answer: 15504

Step-by-step explanation:

Given : The center for research in data science has a vacancy of 5 interns under a research attachment program.

Number of students applied = 20

The combination of n people taking r at a time is given by :-

$C(n,r)=\dfrac{n!}{r!(n-r)!}$

Since, all students fulfill the minimum CGPA criteria it means all 20 students are equally eligible.

Then , the number of ways to select a team of 5 interns from all 20 interns :-

$C(20,5)=\dfrac{20!}{5!(20-5)!}\\\\=\dfrac{20\times19\times18\times17\times16\times15!}{5!15!}\\\\=15504$

Hence, the number of ways to select a team of 5 interns. =

7 0

3 years ago

The spoke of a wheel reaches from the center of the wheel to its rim. If the circumference of the rim of the wheel is 27 inches,

ipn [44]

Circumference = 2 x pi x radius
27 in = 2 x 3.14 x radius

Solve for the radius

5 0

3 years ago

At a zoo, 7 monkeys ate 35 bananas in one day. At

Ray Of Light [21]

Answer: 105

Step-by-step explanation: 35 divided by 7 = 5 , so one monkey eats 5 bananas. 21 x 5 = 105

Hope this helps!

8 0

3 years ago

Read 2 more answers

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st

Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so $\mu = 0.5, \sigma = 0.05$ .