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Alekssandra [29.7K]
3 years ago
8

Sheldon has a traditional health insurance plan. He has a $200 deductible. The level of co-insurance for his plan is 90/10, wher

e 10 represents Sheldon’s portion. He does not have a co-payment. If Sheldon incurs a $1,500 hospital bill, how much money will the insurance company cover for?
Mathematics
2 answers:
Dafna1 [17]3 years ago
7 0

Answer:

$1170

Step-by-step explanation:

Helga [31]3 years ago
6 0
The percentage that the health insurance will be 90% of the price after the deduction has made so the bill will be deducted and the money that will the insurance company cover for is $1170. I hope you are satisfied with my answer and feel free to ask for more
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Write the equation of a circle with a center at (6, 7) and a diameter of 4.
posledela

Answer:

(x - 6)² + (y - 7)² = 4

Step-by-step explanation:

Equation of circle: (x - h)² + (y - k)² = r²

Given center(h,k) = (6,7)

h = 6

k = 7

Dimeter = 4 --

radius, r = \frac{4}{2} = 2

(x - h)² + (y - k)² = r²

(x - 6)² + (y - 7)² = 2²

(x - 6)² + (y - 7)² = 4


8 0
3 years ago
Rita car can travel 35 miles on one gallon of gas she needs she needs to trace 157.5 miles how many gallons of gas will she need
Otrada [13]
You would do 157.5/35 to find how much gas she needs

157/35=4.5
She'll need 4.5gallons of gas
3 0
3 years ago
Matt wants to play in the sand pit, and then try the swings, the slide, and the seesaw, in that order. If the units on the coord
Nataly [62]

Answer:

it should be 12

i think :)

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
3 years ago
Two trains leave the station at the same, one heading west and the other east. The westbound train travels at 55 miles per hour.
Mars2501 [29]

The time that taken for the two trains is 1.2 hours.

The computation of the time taken for the two trains is shown below:

Given that

The westbound train travels 55 miles per hour.

And, the eastbound train travels 75 miles per hour.

So, the total speed is

= 55 miles per hour + 75 miles per hour

= 130 miles per hour

The distance is 156 miles

So, the time taken is

= \frac{distance}{speed}\\\\= \frac{156\ miles}{130\  miles\ per\ hour}\\\\

= 1.2 hours

Therefore we can conclude that the time that taken for the two trains is 1.2 hours.

Learn more about the speed here: brainly.com/question/21791162

4 0
3 years ago
Read 2 more answers
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