Considering the situation described, the classification of the elections is given as follows:
- David came in first place.
- Greg came in second place.
- Victor came in third place.
- Mac came in fourth place.
- Bill came in fifth place.
<h3>How to find the classification of the elections?</h3>
We take the situation that is described, and build the classification from it. The classification has the following format:
P1 - P2 - P3 - P4 - P5
With P1 being the first placed candidate, P2 being the second placed candidate, and so on until P5 which is the fifth placed candidate.
From the text given in this problem, we have that:
- Victor finished in third place, and David beat him, hence P3 = Victor, David = P1 or P2.
- Greg didn't come in first nor in last, hence, considering that Victor is P3, Greg = P2 or P4.
- Mac didn't win, but he finished higher than Bill, hence, considering that Mac didn't win and that Victor is P3, Mac = P4, Bill = P5.
- From the bullet points above, we can conclude that David = P1, Greg = P2.
Hence the places of each candidate are given as follows:
- David came in first place.
- Greg came in second place.
- Victor came in third place.
- Mac came in fourth place.
- Bill came in fifth place.
A similar problem, in which a situation is interpreted, is given at brainly.com/question/5660603
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OK.
Let's say a member and a non member each visit the garden ' V ' times.
The non-member's cost for each visit is $6 .
The non member's cost for ' V ' visits is 6 V .
His total cost for the year is 6 V .
The member's cost for each visit is $3.
The member's cost for ' V ' visits is 3V .
His total cost for the year is 3V + the $24 to join.
We want to know what ' V ' is (how many times each one can visit)
if their total costs are the same.
So let's just write an equation that SAYS their costs are the same,
and see what ' V ' turns out to be.
Non-member's cost for the year = Member's cost for the year
6 V = 3 V + 24
Subtract 3V from each side: 3 V = 24
Divide each side by 3 : V = 8 .
-- If they both visit the garden 1, 2, 3, 4, 5, 6, or 7 times in the year,
the member will spend MORE than the non member.
-- If they both visit the garden 8 times in the year,
they'll both spend the same amount. ($48)
-- If they both visit the garden MORE than 8 times in the year,
the member will spend LESS than the non-member.
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That was the algebra way to do it.
Now here is the cheap, sleazy, logical, easy way to do it:
The non-member spends (6 - 3) = $3 MORE than the member for each visit ?
After how many visits does the $3 more each time add up to the $24 that
it cost the member to join for the year ?
$24 / $3 = 8 visits .
Answer:
100
Step-by-step explanation:
Here is your answer
Let the number of wizards is x
20% more gobins than wizards.
ATQ
Hence Numbers of wizards are 100 in a magic club.
Answer:
i don't speak spanish
Step-by-step explanation:
