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Lelechka [254]
4 years ago
12

Which story problem could be solved using the given equation? 1/5×2/3=m

Mathematics
2 answers:
Dima020 [189]4 years ago
8 0

The right answer is the second word problem :>

Ksju [112]4 years ago
5 0
 its b. hope this helps i guess
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Question
GuDViN [60]
A, because its the exact opposite of what the previous statement says.
6 0
3 years ago
A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h
mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed  = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere  =\frac{2}{3}\pi r^3

Volume of a Cylinder =\pi r^2 h

Therefore:

The Volume of the Solid formed

=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Area of the Hemisphere =2\pi r^2

Curved Surface Area of the Cylinder =2\pi rh

Total Surface Area=

2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh

Cost of the Hemispherical Ends  = 2 X  Cost of the surface area of the sides.

Therefore total Cost, C

=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh

Recall: h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Therefore:

C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}

The minimum cost occurs at the point where the derivative equals zero.

C^{'}=\frac{-27840+32\pi r^3}{3r^2}

When \:C^{'}=0

-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518

Recall:

h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0
3 years ago
A 25% vinegar solution is combined with triple the amount of a 45% vinegar solution and a 5% vinegar solution resulting in 20 mi
Murrr4er [49]

Complete Question: A 25% vinegar solution is combined with triple the amount of a 45% vinegar solution and a 5% vinegar solution resulting in 20 milliliters of a 30% vinegar solution.

Write an equation that models this situation and explain what each part represents in the situation. Then solve the equation.

Step-by-step explanation:

let the volume of the 45% vinegar solution be x litres ,

the volume of the 25% vinegar solution be 3x

and the volume of the 5% vinegar solution be y

summation of all gives,

x+3x+y = 20

4x + y = 20

subtracting 4x from both sides to make y the subject of the equation, we have;

y = 20 - 4x

To the concentration:

substituting for the value of x and y into equation x + 3x + y = 20, we have,

.45x + .25(3x) + .05(20-4x) = .3(20)

multiplying through by 100  to make whole figures we have;

45x + 25(3x) + 5(20-4x) = 600

45x + 75x + 100 - 20x = 600

120x - 20x + 100 = 600

100x + 100 = 600

subtracting 100 from both sides, we have;

100x = 600 - 100

100x = 500

dividing both sides by 100,

x = 5.

7 0
3 years ago
Roy has 5 pounds of dried fruit to make snack bags. He separates each pound of dried fruit into thirds and wants to use 1 third
Dahasolnce [82]

Answer:

15

Step-by-step explanation:

1 turns in to 3 and you multiply that by 5

5 0
3 years ago
Evaluate the following division: (3b-6a)÷(30a-15b)​
shutvik [7]

Evaluate the following division: (3b-6a)÷(30a-15b) is <u>-</u><u>1</u><u>/</u><u>5</u><u>.</u>

<h2><u>INTRODUCTION</u></h2>

~ Algebraic Forms and their Elements

Algebraic form is a mathematical form whose presentation involves symbols or letters to represent unknown numbers.

Elements of Algebra:

1. Variables, Constants and Coefficients

Pay attention to the algebraic form 3x + 2y + 3

From the algebraic form above, x and y are variables (variables), while the number 3 is a constant. A variable is a substitute symbol for a number whose value is not clearly known. While constants are terms of an algebraic form in the form of numbers and do not contain variables.

And what is meant by the coefficient is the constant factor of a term in algebraic form. The coefficient on the 3x term is 3, on the 2y term it is 2.

2. Terms and Factors

» The term is part of the algebraic form which is limited by the operation of addition (+) or difference (-). The term one is an algebraic form that is not connected by the operation of addition or difference.

Example: 2x, 2a², -4xy, . . .

» Term two is an algebraic form that is connected by an operation of sum or difference.

Example: 2x + 3, a² - 4, 3x² - 4x, . . .

» Similar terms in algebraic form are terms that have the same variable and the same power.

Example:

2a is similar to 3a, 4a, etc.

» Factors are part of the algebraic form that is restricted to multiplication operations.

Example: 5n = 5 × n, 5 and n are factors of 4n, respectively.

Calculation Operations on Algebraic Forms

1. Addition and subtraction of algebraic forms can only be done on similar terms.

2. Multiplication and division of algebraic forms.

Multiply two terms by constants or variables.

Example:

3 (4y + 5)

= (3 × 4y) + (3 × 5)

= 12y + 15

Division of two terms with a variable or constant, for example:

(8y+4)/2 = 8y/2 + 4/2 = 4y + 2

<h2><u>DISCUSSION</u></h2>

(3b-6a)÷(30a-15b)

= (-6a + 3b) ÷ (-5(-6a+3b))

= (-6a+3b)/(-5(-6a+3b))

= -1/5

<h3>Conclusion:</h3>

So, Evaluate the following division: (3b-6a)÷(30a-15b) is -1/5.

<h3>Learn More:</h3>

(mampir ke indo:v)

  1. Algebraic subtraction material: https://brainly.co.id/task/35216852
  2. Algebraic arithmetic operations: https://brainly.co.id/task/26250852
  3. The equation of the value of x in algebraic form: https://brainly.co.id/task/42124780

_____________

<h3>Answer Details:</h3>

Class: 7 Middle School

Subject: Math

Material: Chapter 2.1 -Operations of Algebraic Forms

Categorization Code: 7.2.2.1

Keywords: Simple form of algebra

7 0
2 years ago
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