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3 years ago

-6x – 2y-z=-17 5x + y - 6z = 19 -4x - 6y-6z =-20 solve for x, y, and z

Mathematics

1 answer:

Cloud [144]3 years ago

3 0

Answer:

z=17−6x−2y

y=19−5x+6z

x=5−3y/2−3z/2

Step-by-step explanation:

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Please help solve for x..

aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

$x^{100}-4^x \cdot x^{98}-x^2+4^x=0$

Factor out -1:

$\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0$

Divide both sides by -1:

$\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0$

Rearrange the terms:

$\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0$

$\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:$

$\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0$

Factor the first two terms and the last two terms separately:

$\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0$

Factor out the common term $(x^{98}-1)$ :

$\implies (4^x-x^2)(x^{98}-1)=0$

<u>Zero Product Property</u>: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the <u>Zero Product Property</u>, set each factor equal to zero and solve for x (if possible):

$\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}$

Therefore, the solutions to the given equation are: x = 1 or x = -1

Learn more here:

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1 year ago

Jessie claims that if any number is doubled and then increased by 1, the result will be greater than 4.

Kamila [148]

Answer:

n = 1

Step-by-step explanation:

1 x 2 = 2
2 + 1 = 3
3 < 4

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stiv31 [10]

Answer:

Reason 3: Definition of sine.

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Reason 6: Division property of equality

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3 years ago

Graph y−5=−23(x+9) using the point and slope given in the equation.

Mashcka [7]

Answer:

Plot (-9,5) then you do rise over run and go down 2 and to the right 3

Step-by-step explanation:

So your points would be (-9,5) and(-6,3)

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2 years ago

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mars1129 [50]

Answer:

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