7/8+9/10=71/40=1 31/40
1/4+2/3=11/12
1/2+1/4 is different from 1/2+1/3 because
1/2+1/4= 2/4+1/4= 5/1 =1 1/4
1/2+1/3=3/6+2/6=5/6
Answer:
-3x^2-22x-7
Step-by-step explanation:
Answer:
The values of x for which the model is 0 ≤ x ≤ 3
Step-by-step explanation:
The given function for the volume of the shipping box is given as follows;
V = 2·x³ - 19·x² + 39·x
The function will make sense when V ≥ 0, which is given as follows
When V = 0, x = 0
Which gives;
0 = 2·x³ - 19·x² + 39·x
0 = 2·x² - 19·x + 39
0 = x² - 9.5·x + 19.5
From an hint obtained by plotting the function, we have;
0 = (x - 3)·(x - 6.5)
We check for the local maximum as follows;
dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0
6·x² - 38·x + 39 = 0
x² - 19/3·x + 6.5 = 0
x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2
∴ x = 1.288, or 5.045
At x = 1.288, we have;
V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99
V ≈ 22.99 in.³
When x = 5.045, we have;
V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023
Therefore;
V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5
The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.
Answer:
the answer is 7 over 9932!
Step-by-step explanation:
Answer:
The prevalence rate of flu cases requiring hospitalization thus far in 2018 is:
= 0.13%
Step-by-step explanation:
a) Data and Calculations:
Population of Portland, ME = 70,000
Number of flu cases requiring hospitalization on February 1st, 2018 = 43
Number of flu cases requiring hospitalization on July 4th, 2018 = 90
The prevalence rate of flu cases requiring hospitalization thus far in 2018 = 90/70,000 * 100 = 0.13%
b) The prevalence rate represents the proportion of the population of Portland, ME, who have the flu at the time that the Maine Public Health Department reported the number of flu cases requiring hospitalization on July 4th, 2018.
