Which shape has only acute angles?

Mathematics

1 answer:

olga nikolaevna [1]2 years ago

5 0

The triangle has an only acute angle

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a car left town A at 10:00 am and travelled towards town B at the average speed of 70 km/h. At the same time a truck left town B

Softa [21]

The important formula to this problem is $distance=rate(time)$ or $d=rt$

Now, the speed of the car is 70 km/h, and the speed of the truck is 50 km/h. It will take the two vehicles the same amount of time to meet since they both left at the same time. So, since distance equals rate times time, and t = time:

the distance of the car = 70t
the distance of the truck = 50t

Because they both left in opposite directions, and the towns are 420 kilometers apart, the equation for this would be

$70t+50t=420$

We now solve the equation.

$70t+50t=420 \\ 120t=420 \\ \frac{120t}{120}= \frac{420}{120} \\ t=3 \frac{1}{2}$

It will take the vehicles 3 and a half hours to meet. Since we're looking for the time, 3 and a half hours from 10:00 AM is 1:30 PM.

So, the car and the truck will pass each other at 1:30 PM.

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2 years ago

Given the ordered pair P, determine the requested sin, cos, or tan of angle . P(4, 5) sin = (4√41)/41 (5√41)/41 4/5 5/4 what is

Viefleur [7K]

Ok One side would have a length of 4, another side would have a length of 5, and then we can use the Pythagorean Theorem to find the length of the hypotenuse. a^2 + b^2 = c^2 

a=4; b=5; 

4^2 + 5^2 = c^2 
16 + 25 = c^2 
41 = c^2 
c = √41 

Therefore, the hypotenuse has a length of √41. 

To find the sinθ, you take the opposite over the hypotenuse. 

Remember when you drew out the triangle? θ is the angle connected to the origin. The opposite side is b, which is 5. 

Your answer is 5/√41. 

This answer must be simplified since there is a radical in the denominator. To simplify, you can just multiply the numerator and the denominator by √41/√41 (since this is equivalent to 1). 

This gives you the answer

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