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bagirrra123 [75]
3 years ago
5

Write the equation of the line fully simplified slope-intercept form​

Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

y=mx+b

Step-by-step explanation:

standard slope intercept form. just plug in slope and intercept

You might be interested in
Part A: Find the LCM of 7 and 12. Show your work. (3 points)
anyanavicka [17]

The LCM of 7 and 12 is 84 and GCF of 56 and 96 is 8, 56+96 can be written as 8(19).

<h3>What is LCM?</h3>

It is defined as the common number of two integers, which is the lowest number that is a multiple of the two or more numbers. The full name of LCM is the least common multiple.

LCM of 7 and 12:

7 can be divided by 7

Factor of 12 is 2×2×3

So the LCM = 7×2×2×3 = 84

For GCF:

We know:

GCF(56, 96) = (56×96)/LCM(56, 96)

GCF(56×96) = (56×96)/672 = 8

= (56 + 96)

= 8(7+12)

= 8(19)

Thus, the LCM of 7 and 12 is 84 and GCF of 56 and 96 is 8, 56+96 can be written as 8(19).

Learn more about the LCM here:

brainly.com/question/20739723

#SPJ1

3 0
2 years ago
Trait theorists have analyzed and grouped large numbers of _____ traits in order to identify a smaller number of _____.
sattari [20]
Subscribe to kadevan fitness on YouTube
6 0
4 years ago
Last Saturday, Neha walked all over town running errands. First, she walked 3/11 of a mile from her house to the library and 1/1
pishuonlain [190]
3 + 1 +10 = 14

hint: 1 mile = 11/11 miles

She walked 14/11 miles = 1 and 3/11 miles
5 0
3 years ago
The number of cars running a red light in a day, at a given intersection, possesses a distribution with a mean of 2.4 cars and a
liberstina [14]

Answer:

The sampling distribution of the sample mean is:

\bar X\sim N(\mu_{\bar x}=2.4,\ \sigma_{\bar x}=0.40)

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Let <em>X</em> = number of cars running a red light in a day, at a given intersection.

The information provided is:

E(X)=\mu=2.4\\SD(X)=\sigma=4\\n=100

The sample selected is quite large, i.e. <em>n</em> = 100 > 30.

The Central limit theorem can be used to approximate the sampling distribution of the sample mean number of cars running a red light in a day, by the Normal distribution.

The mean of the sampling distribution of the sample mean is:

\mu_{\bar x}=\mu=2.4

The standard deviation of the sampling distribution of the sample mean is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{4}{\sqrt{100}}=0.40

The sampling distribution of the sample mean is:

\bar X\sim N(\mu_{\bar x}=2.4,\ \sigma_{\bar x}=0.40)

8 0
3 years ago
Choose Equivalent or Not Equivalent <br><br> a. 6(3x+5) and 18x+30 <br><br> b. 12y+3 and 3y+12
ELEN [110]
I think it is B
Hope my answer help you?
5 0
3 years ago
Read 2 more answers
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