To solve this question, we use the factor theorem, and using it, the polynomial function is:

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The factor theorem means that if k is a root of f(x), f(k) = 0.
Thus, applying the factor theorem for this question, we have to choose the function for which: 
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Function 1:

Testing the values:



Thus, since all three conditions are satisfied,
is the polynomial function.
A similar question is given at brainly.com/question/11378552
If you only used 13% then you used 4.42 pounds of dry ice.
Step-by-step explanation:
try 5 hope this helped you