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denis23 [38]
3 years ago
9

Find the area of this circle. Use 3 for pi

Mathematics
2 answers:
Svetlanka [38]3 years ago
6 0

Answer:

A = 147 cm²

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Area of a Circle Formula: A = πr²

  • <em>r</em> is radius

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em>r</em> = 7 cm

<u>Step 2: Find Area</u>

  1. Substitute in variables [Area of a Circle Formula]:                                         A = 3(7 cm)²
  2. Evaluate exponents:                                                                                         A = 3(49 cm²)
  3. Multiply:                                                                                                             A = 147 cm²
ohaa [14]3 years ago
5 0

Step-by-step explanation:

given pi value= 3

radius=7

we know,

area of a circle(A)= πr²

= 3×7²

=147cm²

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vova2212 [387]
Idk if this helps but answer that i got was. ) X1=-1,x2=^33/2
4 0
3 years ago
Solve : x + 1/2 + x + 2/3 − x + 3/4 = 2
valentinak56 [21]

Answer:

x= 1 7/12

Step-by-step explanation:

x+1/2+x+2/3-x+3/4=2

1. We know that x+x-x=x

2. 1/2+2/3-3/4=6/12+8/12-9/12=5/12

3. x+5/12=2

4. x=2-5/12

x=1 7/12

8 0
3 years ago
Read 2 more answers
Bad gums may mean a bad heart. Researchers discovered that 79% of people who have suffered a heart attack had periodontal diseas
zysi [14]

Answer:

(A) 0.297

(B) 0.595

Step-by-step explanation:

Let,

H = a person who suffered from a heart attack

G = a person has the periodontal disease.

Given:

P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.15)+(0.33\times(1-0.15))\\=0.399

(A)

The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.15}{0.399} \\=0.29699\\\approx0.297

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.

(B)

Now if the probability of a person having a heart attack is, P (H) = 0.38.

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.38)+(0.33\times(1-0.38))\\=0.5048

Compute the probability of a person having a heart attack given that he or she has the disease:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.38}{0.5048}\\ =0.59469\\\approx0.595

The probability of a person having a heart attack given that he or she has the disease is 0.595.

4 0
3 years ago
Math help plz! Check for extraneous solutions. Giving brainlist
Dima020 [189]
This is number 8. the second person got number 9

4 0
4 years ago
MATHS
Snowcat [4.5K]

Answer:

1. 50000

2.

i 274625000cm

ii 274.625m

Step-by-step explanation:

1. Area of a rectangle: length*width

250*200=50000cm

2. Volume of a cube: length^3

i 650^3=274625000cm

ii 650 cm=6.5m; 6.5^3=274.625m

8 0
3 years ago
Read 2 more answers
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