-(-2) ...................................................
1 answer:
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Answer:
a. Outcomes of A = { (C,C,C) , (D,D,D), (S,S,S) }
b. Outcomes of B = { (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }
c. Outcomes of C = { (C,C,C),(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }
d. Outcomes of A⋂C = { (C,C,C) }
e. Outcomes of Sample space = { (C,C,C), (C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S), (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }
f. Outcomes of A U B = { (C,C,C) , (D,D,D), (S,S,S), (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }
g. Outcomes of A⋂ = { (D,D,D), (S,S,S) }
h. Outcomes of ⋂C = {(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C)}
i. Events A and C are not mutually exclusive
j. Events B and C are mutually exclusive
Step-by-step explanation:
Given - Three times each day, a quality engineer samples a component
from a recently manufactured batch and tests it. Each part is
classified as conforming (suitable for its intended use),
downgraded (unsuitable for the intended purpose but usable for
another purpose), or scrap (not usable). An experiment consists
of recording the categories of the three parts tested in a particular
day.
To find - a. Let A be the event that all the parts fall into the same
category. List the outcomes in A.
b. Let B be the event that there is one part in each category.
List the outcomes in B.
c. Let C be the event that at least two parts are conforming.
List the outcomes in C.
d. List the outcomes in A⋂C
e. List the 27 outcomes in the sample space.
f. List the outcomes in A U B.
g. List the outcomes in A⋂
h. List the outcomes in ⋂C.
i. Are events A and C mutually exclusive? Explain.
j. Are events B and C mutually exclusive? Explain.
Proof -
Let
Conforming part = C
Downgraded part = D
Scrap part = S
a.)
Given , Let A be the event that all the parts fall into the same category.
Outcomes of A = { (C,C,C) , (D,D,D), (S,S,S) }
b.)
Given, Let B be the event that there is one part in each category.
Outcomes of B = { (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }
c.)
Given, Let C be the event that at least two parts are conforming.
Outcomes of C = { (C,C,C),(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }
d.)
Outcomes of A⋂C = { (C,C,C) }
e.)
Outcomes of Sample space = { (C,C,C), (C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S), (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }
f.)
Outcomes of A U B = { (C,C,C) , (D,D,D), (S,S,S), (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }
g.)
Outcomes of = { (C,D,D), (C,D,S), (C,S,D), (C,S,S), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }
Outcomes of A⋂ = { (D,D,D), (S,S,S) }
h.)
Outcomes of = {(C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C), (D,D,S), (D,S,C), (D,S,D), (D,S,S), (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), }
Outcomes of ⋂C = {(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }
i.)
As we two that Two events A and C are mutually exclusive iff A ∩ C = ∅
Now,
A ∩ C = { (C,C,C) }
⇒Events A and C are not mutually exclusive.
j.)
As we two that Two events B and C are mutually exclusive iff B ∩ C = ∅
Now,
B ∩ C = ∅
⇒Events B and C are mutually exclusive.
<h3>Answer: 3/10 of a shed</h3>
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Explanation:
Let's say the shed comes in 40 equal pieces. Each piece takes the same amount of time to assemble. Why am I picking 40? Because 8*5 = 40.
This will allow us to rewrite the fractions with a common denominator.
- 1/5 = 8/40 .... multiply top and bottom by 8
- 5/8 = 25/40 .... multiply top and bottom by 5
So Jack can build 8/40 of the shed in the same amount of time Kyle can build 25/40 of the shed.
Instead of writing fractions (which honestly are a pain to deal with), I'm going to write "8 pieces" and "25 pieces" to represent "8/40" and "25/40" respectively. Just keep in mind that there are 40 pieces total.
So again, Jack can assemble 8 pieces in the time it takes Kyle to assemble 25 pieces.
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The ultimate goal is to have Kyle assemble 40 pieces while Jack puts together some unknown number of pieces (some number between 8 and 40). Let's say it's x.
We can then form this proportion
which simplifies or cleans up to
5/x = 25/40
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Let's solve for x using cross multiplication
8/x = 25/40
8*40 = x*25
320 = 25x
25x = 320
x = 320/25
x = 12.8
So in the time it takes Kyle to assemble all 40 pieces, Jack can put together 12.8 pieces of the shed. However, we can't have Jack put together some fractional piece, because each "piece" is as small as it gets. We can't get any smaller. It would be like saying a fractional part of an atom or a lego block.
So we'll round 12.8 down to 12.
Jack can assemble 12 pieces in the time it takes Kyle to assemble 40 pieces.
Let's then convert this back to fraction form
12 pieces = 12/40 of a shed = 3/10 of a shed.