Answer:
Option B is correct.
Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.
Step-by-step Explanation:
The clear, complete table For this question is presented in the attached image to this solution.
It should be noted that For this question, the running coach wants to test if participating in weekly running clubs significantly improves the time to run a mile.
In the data setup, the mean time to run a mile in January for those that participate in weekly running clubs and those that do not was provided.
The mean time to run a mile in June too is provided for those that participate in weekly running clubs and those that do not.
Then the difference in the mean time to run a mile in January and June for the two classes (those that participate in weekly running clubs and those that do not) is also provided.
Since, the aim of the running coach is to test if participating in weekly running clubs significantly improves the time to run a mile, so, it is logical that it is the improvements in running times for the two groups that should be compared.
Hence, we should use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.
Hope this Helps!!!
It might be 2/9 sorry if it wasn’t
Answer:
$14.9
Step-by-step explanation:
238.40 / 16 = $14.9 hourly
1. Exponential Function
2. Quadratic Function
3. Piecewise Function
4. Absolute Value Function
5. Is choice 4
Answer:
$18
Step-by-step explanation:
Let's subtract the lunch from the trip total to get the remainding cost!
36.50 - 9.50 = $27
Now let's set up an equation to figure out the amount of the entrance ticket and the gift coupon!
let's have x = the entrance ticket
27 = x + 1/2(x) -----------> 1/2 is next to x, because the gift coupon is 1/2, or 50% of the entrance ticket! Now solve for x!
27 = 3/2x
(2/3) 27 = 3/2x (2/3)
18 = x, so the entrance ticket is $18!