A set of 3 consecutive integers has a sum of 27. which integers are they
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All we want to do is get an equation with just x on one side and no x's on the other.
We can use inverse operations to accomplish this.
First, bring bx to the left side. Subtract the 3.
Factor ax+bx to x(a+b). (this is pretty much reversing the distributive property)
Divide by a+b and you are left with just x on the left side as 4/(a+b).
We can use inverse operations to accomplish this.
First, bring bx to the left side. Subtract the 3.
Factor ax+bx to x(a+b). (this is pretty much reversing the distributive property)
Divide by a+b and you are left with just x on the left side as 4/(a+b).