The confidence level C and the significance level alpha are linked through the equation
alpha = 1-C
So for instance, if the confidence level is C = 95% = 0.95 then alpha is
alpha = 1-C
alpha = 1-0.95
alpha = 0.05
meaning we have a 5% significance level. The larger C gets, the smaller alpha gets and vice versa. It turns out that 0 < C < 1 and also 0 < alpha < 1.
The closer C gets to 1, the alpha value gets closer to 0. The smaller alpha gets, the harder it is to reject the null. Why is that? If we have a fixed p value, say p = 0.02 then we reject the null if alpha > pvalue. But we fail to reject the null when alpha < pvalue. For very small alpha values, we're going to fail to reject H0 no matter how small the pvalue is. The pvalue would have to be really small for H0 to be rejected.
In short, I'm saying that if the confidence level is high, then the chance of rejecting the null hypothesis is low (or rare)
This is why the answer is choice A
Answer:
280 customers
Step-by-step explanation:
80% of 350 is 280
Hi! :)
What is f(-2)?
See that f(x) is 1 when x = -2. That is f(-2) = 1.
Hope this helps, good studies.
Answer:
6072.444
Step-by-step explanation:
x = 5,500(1+0.02)^5
A graph of this equation y - 2 = -3/4(x - 6) is shown in the image attached below.
<h3>What is a graph?</h3>
A graph can be defined as a type of chart that is typically used for the graphical representation of data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-coordinate and y-coordinate.
Next, we would rearrange and simplify the given given equation in slope-intercept form in order to enable us plot it on a graph:
y - 2 = -3/4(x - 6)
Opening the bracket, we have:
y - 2 = -3x/4 + 18/4
y = -3x/4 + 18/4 + 2
y = -3x/4 - 26/4
y = -3x/4 - 13/2
Therefore, the slope is equal to -3/4 and the y-intercept is equal to -13/2.
In conclusion, we can logically deduce that the graph representing the given linear equation does not show a proportional relationship between the value of x and y.
Read more on graphs here: brainly.com/question/4546414
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