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klasskru [66]
2 years ago
11

Please help me solve these problems.

Mathematics
1 answer:
natali 33 [55]2 years ago
5 0
1. B
2. I'm not sure but I think it's D
3. C
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Simplify using a table. Can someone help?
Alona [7]
The product is -10y² -19y +15.

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3 years ago
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A(x+y)-a(x-y) simplified .
Keith_Richards [23]

Answer:

2ay

Step-by-step explanation:

a(x+y)-a(x-y)

Distribute

ax +ay - ax + ay

Combine like terms

2ay

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3 years ago
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What is the value of the expression (–5) -3 but the -3 is an exponent.
Vanyuwa [196]

Answer:

Answer: -0.008

Step-by-step explanation:

Hope this helped!

6 0
3 years ago
Stormer Company reports the following amounts on its statement of cash flow: Net cash provided by operating activities was $37,0
olchik [2.2K]

Answer:

The ending cash balance is $12,800

Step-by-step explanation:

This is an addition and subtraction problem. We begin with the initial cash balance of $6,800. Next we are <u>"provided"</u> cash from various activities of $37,000. Based on the word used we can tell that this means we have to <em>add </em>this to our initial balance like so,

6,800 + 37,000 = 43,800

Now our balance is $43,000. Next we are told that Net Cash <u>"used"</u> in investing activities is $13,600 and <u>"used"</u> in financing activities is $17,400. Based on this word we can tell that this money is being <em>subtracted</em> from our balance.

$43,000 - 13,600 - 17,400 = 12,800

Finally, we can see that the ending cash balance is $12,800

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

7 0
3 years ago
Determine whether the relationship is an inverse variation or not. Explain.
kolbaska11 [484]

Answer: The product xy is not constant, so the relationship is not an inverse variation.

Step-by-step explanation:

For it to be an inverse variation, the product of x and y must be constant.

  • For the first row, xy=2(424)=848.
  • For the second row, xy=3(280)=840.
  • For the third row, xy=4(210)=840.

This means <u>the product xy is not constant, so the relationship is not an inverse variation.</u>

8 0
1 year ago
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