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Helen [10]
2 years ago
12

Please help with scale factor!!!!!!!! I will mark brainliest if right! Two rectangular prisms have a side scale factor of 1/4. I

f the smaller prism has a surface area of 45cm square, what is the surface area of the larger prism? Find the scale factor and area.
Mathematics
1 answer:
Agata [3.3K]2 years ago
5 0

Answer:

  • 1/16
  • 720 cm²

Step-by-step explanation:

Area is the product of two dimensions.

<u>If the scale factor is 1/4, the ratio of the areas will be: </u>

  • (1/4)² = 1/16

The smaller prism has a surface are of 45 cm².

<u>The larger prism has a surface area:</u>

  • 45*16 = 720 cm²
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Nate has a bag containing 3 red, 2 blue, 4 yellow, and 3 green marbles. If he randomly chooses one marble from the bag, what is
SVEN [57.7K]

<u>The probability that the marble will be blue if he shakes the bag and when you puts his hand into the bag, to move it around and probably he'll get the blue marble.</u>

<em>Hopefully, it correct.... :)</em>

4 0
2 years ago
Hailey is knitting a scarf. Each half hour, she adds 3/7 inch to the scarf's length. How much length will she add to the scarf i
BARSIC [14]
Take 3/7 and multiply it by 2 to find out how much she knits in one hour. Then take that value and multiply by 12 to find out how much she knits in 12 hours.

3/7 x 2 = 6/7
6/7 x 12 = 72/7 or 10 2/7.
7 0
3 years ago
Question 2 -of 15 Step 1 of 1No Time LimitA company manufactures two products. One requires 5 hours of labor, 3 poundsof raw mat
elena-14-01-66 [18.8K]

the cost of labour per hour is $7.20

the cost of raw materials per pound is $11.60

Explanation:

For product one:

time = 5 hours of labour

let the cost labour per hour = x

Amount = 3 pounds of raw amterials

let the cost of one pound raw material = y

Cost to produce each product = $70.8

The equation:

time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product

5(x) + 3(y) = 70.80

5x+3y=70.8....\mleft(1\mright)

For product 2:

time = 3.5 hours of labour

let the cost of labour per hour = x

Amount = 13 pounds of raw amterials

let the cost of one pound raw material = y

Cost to produce each product = $176.00

The equation:

time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product

3.5(x) + 13(y) = 176

3.5x+13y=176\text{   .... (2)}

combining both equations:

5x + 3y = 70.8 ...(1)

3.5x + 13y = 176 ....(2)

Using elimination method:

To eliminate y, we will multiply equation (1) by 13 and equation (2) by 3 so that both coefficient of y become the same

65x + 39y = 920.4 ...(*1)

10.5x + 39y = 528 ...(2*)

subtract equation (2*) from (1*):

65x - 10.5x + 39y - 39y = 920.4 - 528

54.5x + 0 = 392.4

54.5x = 392.4

divide both sides by 54.5:

x = 392.4/54.5

x = 7.2

substitute for x in any of the equations

Using equation 1: 5x + 3y = 70.8

\begin{gathered} 5\mleft(7.2\mright)+3y=\text{ 70.8} \\ 36\text{ + 3y = 70.8} \\ 3y\text{ = 70.8 - 36} \\ 3y\text{ = 34.8} \\  \\ \text{divide both sides by 3:} \\ \frac{3y}{3}=\frac{34.8}{3} \\ y\text{ = }11.6 \end{gathered}

Hence, the cost of labour per hour is $7.20 and the cost of raw materials per pound is $11.60

6 0
1 year ago
As a town gets​ smaller, the population of its high school decreases by 4% each year. The senior class has 320 students now. In
Mice21 [21]

Answer:

  • c(n) = 320·0.96^n
  • 28 years

Step-by-step explanation:

Each year, the class size is multiplied by 1 - 4% = 96% = 0.96. After n years, it has been multiplied by that number n times. Repeated multiplication is signified using an exponent.

Class size (c) can be modeled by ...

  c(n) = 320·0.96^n

__

You want to find n such that c(n) = 100. Put in that value and solve.

  100 = 320·0.96^n

  100/320 = 0.96^n . . . . . . . divide by 320

  log(100/320) = n·log(0.96) . . . . . . . take logs

  log(100/320)/log(0.96) = n ≈ 28.4932

In about 28 years, the class will have 100 students.

8 0
3 years ago
I need to find the value of x
tangare [24]

Answer:

x = \sqrt{21}

Step-by-step explanation:

AC² = AB² + BC²

BC² = 3² + x² = 9 + x²

AB² = 7² + x² = 49 + x²

But AC² = (7 + 3)² = 100

∴ 100 = 49 + x² + 9 + x²

2x² + 58 = 100

x² = 50 - 29 = 21

x = \sqrt{21}

3 0
2 years ago
Read 2 more answers
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