I believe you're right with what you have
the price decrease being 5% (the .95) and the increase by 15% (the 1.15)
Given that the revenue equation is

and the cost equation is

Part A:
At break-even the cost is equal to the revenue.
Thus, the algebraic equation needed to determine when the company will break even is given by

Part B:
The solution to part A is given as follows:

Part C:
<span>The algebraic inequality needed to indicate that the revenue is greater than the cost is given by

Part D:
</span>The solution to part C is given as follows:

Part E:
The answer in part D tells us that the the company will make a profit when the produce more than 5000 cards.
Answer:
147
Step-by-step explanation:
Average rate of change is given by the total rise over total run.

So,
total rise = 377 - 83 = 294
total run = 2
average rate of change = 
The questions for this problem would be:
1. What is the dimensions of the box that has the maximum volume?
2. What is the maximum volume of the box?
Volume of a rectangular box = length x width x height
From the problem statement,
length = 12 - 2x
width = 9 - 2x
height = x
where x is the height of the box or the side of the equal squares from each corner and turning up the sides
V = (12-2x) (9-2x) (x)
V = (12 - 2x) (9x - 2x^2)
V = 108x - 24x^2 -18x^2 + 4x^3
V = 4x^3 - 42x^2 + 108x
To maximize the volume, we differentiate the expression of the volume and equate it to zero.
V = 4x^3 - 42x^2 + 108x
dV/dx = 12x^2 - 84x + 108
12x^2 - 84x + 108 = 0x^2 - 7x + 9 = 0
Solving for x,
x1 = 5.30 ; Volume = -11.872 (cannot be negative)
x2 = 1.70 ; Volume = 81.872
So, the answers are as follows:
1. What is the dimensions of the box that has the maximum volume?
length = 12 - 2x = 8.60
width = 9 - 2x = 5.60
height = x = 1.70
2. What is the maximum volume of the box?
Volume = 81.872
You add 4 on both sides so the 4 cancels out and you know have 23+4= 27
D=27