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Vesna [10]
2 years ago
8

What would be the expression after distributing, -3(x+5)?

Mathematics
2 answers:
polet [3.4K]2 years ago
7 0

Answer:

-3x-15

Step-by-step explanation:

-3*x

-3*5

sweet-ann [11.9K]2 years ago
3 0

Answer:

-3x - 15

Step-by-step explanation:

to find the expression you would multiply the negative three to both the x and 5, this will give you a -3x and a -15 because the 15 is a negative you wouldn't use the plus sign anymore, instead you would use the negative for the 15

hope this helped! :)

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Tavius wants to invest $2,500. Which option will earn him the best value?
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Tavius would earn his best value if he invests in a  three-year certificate of deposit with a nominal interest rate of 4 percent.

Tavius would invest in the option that yields the highest interest. This is the best value. In order to determine which option is the best, the interest rate of each option has to be determined.

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Interest earned = amount invested x time x interest rate

$2500 x 0.03 x 2 = $150

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<em><u>Interest rate of the second option</u></em>

Interest earned = amount invested x time x interest rate

$2500 x 0.03 x 1 = $75

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<em><u>Interest rate of the third option</u></em>

Interest earned = amount invested x time x interest rate

$2500 x 0.04 x 3 = $300

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<em><u>Interest rate of the fourth option</u></em>

FV = P x (1 + r) n

$2500 x (1.03) = $75

A similar question was answered here: brainly.com/question/24748787?referrer=searchResults

5 0
2 years ago
A turtle and a snail are 300 feet apart when they start moving towards each other. The turtle is moving at a speed of 5 feet per
givi [52]

Answer:

It Is 60

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3 0
3 years ago
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Given that sin(30)=1/2 and cos(30)=(sqrt3)/2, use trigonometric identities to find the value of cot(30)
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<u>Your question: </u>given that sin(30)=1/2 and cos(30)=(sqrt3)/2, use trigonometric identities to find the value of cot(30)

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3 years ago
Determine whether the three points are the vertices of a right triangle.
Jobisdone [24]
Yes I have graphed them and they form a 90 degree angle
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2 years ago
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