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ArbitrLikvidat [17]
3 years ago
7

Please help me with both of these.

Mathematics
1 answer:
Andru [333]3 years ago
3 0
All i know is that the first one is an integer i think.
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What is the length of the hypotenuse? If necessary, round to the nearest tenth.
Papessa [141]

<u>Answer:</u>

  • The value of c is 2√2 or about 2.8.

<u>Step-by-step explanation:</u>

<u>We can find the hypotenuse (c) with the help of Pythagoras Theorem.</u>

  • => c² = 2² + 2²
  • => c² = 4 + 4
  • => c² = 8
  • => c = √8
  • => c = √2 x 2 x 2
  • => c = 2√2

<u>If you want further simplification, seek for explanation below.</u>

  • => c = 2√2
  • => c = 2 x √2
  • => c = 2 x 1.414
  • => c = 2.828 = 2.8 (Estimated)

Hence, <u>the value of c is 2√2 or about 2.8.</u>

Hoped this helped.

BrainiacUser1357

6 0
2 years ago
6x+2(x+4)&lt;2x+20 solve for inequality
8_murik_8 [283]

The problem to solve is:

6x+2(x+4)‹2x+20

First, let's work on the left hand side of your inequality, the 6x+2(x+4)

This means, for instance, to see if it can be simplified at all.

Multiply x and 6

Multiply x and 1

The x just gets copied along.

The answer is x

x

6*x evaluates to 6x

x+4 evaluates to x+4

Multiply 2 by x+4

we multiply 2 by each term in x+4 term by term.

This is the distributive property of multiplication.

Multiply 2 and x

Multiply 1 and x

The x just gets copied along.

x

2 × x = 2x

Multiply 2 and 4

1

2 × 4 = 8

2*(x+4) evaluates to 2x+8

6x + 2x = 8x

The answer is 8x+8

6*x+2*(x+4) evaluates to 8x+8

So, all-in-all, the left hand side of your inequality can be written as: 8x+8

Now, let's work on the right hand side of your inequality, the 2x+20

Multiply x and 2

Multiply x and 1

The x just gets copied along.

The answer is x

x

2*x evaluates to 2x

2*x+20 evaluates to 2x+20

The right hand side of your inequality can be written as: 2x+20

So with these (any) simplifications, the inequality we'll set out to solve is:

8x+8 ‹ 2x+20

Move the 8 to the right hand side by subtracting 8 from both sides, like this:

From the left hand side:

8 - 8 = 0

The answer is 8x

From the right hand side:

20 - 8 = 12

The answer is 12+2x

Now, the inequality reads:

8x ‹ 12+2x

Move the 2x to the left hand side by subtracting 2x from both sides, like this:

From the left hand side:

8x - 2x = 6x

The answer is 6x

From the right hand side:

2x - 2x = 0

The answer is 12

Now, the inequality reads:

6x ‹ 12

To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

around the x on the left side of the inequality.

The last step is to divide both sides of the inequality by 6 like this:

To divide x by 1

The x just gets copied along in the numerator.

The answer is x

6x ÷ 6 = x

12 ÷ 6 = 2

The solution to your inequality is:

x ‹ 2

So, your solution is:

x must be less than 2The problem to solve is:

6x+2(x+4)‹2x+20

First, let's work on the left hand side of your inequality, the 6x+2(x+4)

This means, for instance, to see if it can be simplified at all.

Multiply x and 6

Multiply x and 1

The x just gets copied along.

The answer is x

x

6*x evaluates to 6x

x+4 evaluates to x+4

Multiply 2 by x+4

we multiply 2 by each term in x+4 term by term.

This is the distributive property of multiplication.

Multiply 2 and x

Multiply 1 and x

The x just gets copied along.

x

2 × x = 2x

Multiply 2 and 4

1

2 × 4 = 8

2*(x+4) evaluates to 2x+8

6x + 2x = 8x

The answer is 8x+8

6*x+2*(x+4) evaluates to 8x+8

So, all-in-all, the left hand side of your inequality can be written as: 8x+8

Now, let's work on the right hand side of your inequality, the 2x+20

Multiply x and 2

Multiply x and 1

The x just gets copied along.

The answer is x

x

2*x evaluates to 2x

2*x+20 evaluates to 2x+20

The right hand side of your inequality can be written as: 2x+20

So with these (any) simplifications, the inequality we'll set out to solve is:

8x+8 ‹ 2x+20

Move the 8 to the right hand side by subtracting 8 from both sides, like this:

From the left hand side:

8 - 8 = 0

The answer is 8x

From the right hand side:

20 - 8 = 12

The answer is 12+2x

Now, the inequality reads:

8x ‹ 12+2x

Move the 2x to the left hand side by subtracting 2x from both sides, like this:

From the left hand side:

8x - 2x = 6x

The answer is 6x

From the right hand side:

2x - 2x = 0

The answer is 12

Now, the inequality reads:

6x ‹ 12

To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

around the x on the left side of the inequality.

The last step is to divide both sides of the inequality by 6 like this:

To divide x by 1

The x just gets copied along in the numerator.

The answer is x

6x ÷ 6 = x

12 ÷ 6 = 2

The solution to your inequality is:

x ‹ 2

So, your solution is:

x must be less than 2

7 0
3 years ago
Practice and homework lesson 6.7
suter [353]
Can you plz add a picture to show
4 0
3 years ago
Can you subtract variables with different exponents
Serjik [45]
If you're asking if you can subtract this, for example:

x³ - x²

No.  They must have the same exponent to be compatible.  For example:

4x² - x²  =  3x²
5 0
4 years ago
Read 2 more answers
What is the volume of the container below?
zheka24 [161]

Answer:

C

Step-by-step explanation:

  1. Split the figure into two rectangles
  2. The dimensions of the smaller rectangle on top are: length = 6 width = 10 height = 4
  3. V = 6(10)(4) = 240
  4. The dimensions of the larger rectangle on the bottom are: length = 6 width = 14 height = 16
  5. *You can find the height by subtracting 20 - 4 = 16*
  6. V = 6(14)(16) = 1,244
  7. Add the volumes: 240 + 1,244 = 1,584
  8. The sum, 1,584, is the total volume
4 0
3 years ago
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