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givi [52]
3 years ago
14

If the perimeter of a rectangle is 54 inches. And its length is two times its width. What is the length and the width of the rec

tangle?
Mathematics
1 answer:
konstantin123 [22]3 years ago
8 0

Answer: I cjvchjb

Step-by-step explanation:bjgcjvc

Chhcbbv

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Please help asap. due today
Ksivusya [100]

Answer:

ASA

Step-by-step explanation:

∠BAC ≈ ∠CAD

AC = AC

∠BCA ≈ ∠ACD

5 0
3 years ago
I. Daska is situated at a distance of 15 miles from both Gujranwala and Sialkot. A bus travels from Gujranwala to Daska at an av
son4ous [18]

Answer:

The average speed of the entire trip is 8.5 miles per hour.

Step-by-step explanation:

Speed = Total  Distance / Total Time

So we have to find the total distance and the total time taken .

1) From Gujranwala to Daska

speed= 25miles/hour           distance = 15miles

Time taken = distance / speed

                   = 15/25= 0.6 hours

2)  From Daska to Sialkot

speed= 40miles/hour           distance = 15miles

Time taken = distance / speed

                   = 40/15= 2.67 hours

3 ) From  Sialkot to Daska

speed= 30miles/hour           distance = 15miles

Time taken = distance / speed

                   = 30/15= 2 hours

The total distance traveled to three places is = 15+ 15+15= 45miles

The Total time taken is = 0.6+ 2.67+ 2= 5.267=5.3 hours

Speed = Total  Distance / Total Time

Speed= 45/ 5.3

          = 8.49=8.5 miles per hour

The average speed of the entire trip is 8.5 miles per hour.

7 0
3 years ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3
In-s [12.5K]

Answer:

a) There is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

c) There is a 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3 minutes. This means that \mu = 8.3, \sigma = 3.3.

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

We are working with a sample mean of 37 jets. So we have that:

s = \frac{3.3}{\sqrt{37}} = 0.5425

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

This probability is the pvalue of Z when X = 8.65. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.65 - 8.3}{0.5425}

Z = 0.65

Z = 0.65 has a pvalue of 0.7422. This means that there is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is subtracted by the pvalue of Z when X = 7.43

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.43 - 8.3}{0.5425}

Z = -1.60

Z = -1.60 has a pvalue of 0.0548.

There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is the pvalue of Z when X = 8.65 subtracted by the pvalue of Z when X = 7.43.

So:

From a), we have that for X = 8.65, we have Z = 0.65, that has a pvalue of 0.7422.

From b), we have that for X = 7.43, we have Z = -1.60, that has a pvalue of 0.0548.

So there is a 0.7422 - 0.0548 = 0.6874 = 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

7 0
3 years ago
The integer<br> is neither positive nor negative.
Artist 52 [7]

Answer:

false

Step-by-step explanation:

an integer is any number greater or less than 0

8 0
3 years ago
Find the area. Simplify the answer. 3x and x+6
Ilya [14]
18x .......,,,,..xbxncmd
5 0
3 years ago
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