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Zolol [24]
3 years ago
6

Hey brainly.... Help

Mathematics
2 answers:
katovenus [111]3 years ago
6 0

Answer:

D

hope that answers your question

Step-by-step explanation:

stiv31 [10]3 years ago
5 0

Answer:

D.) Trapezoid

Step-by-step explanation:

A trapezoid is a quadrilateral with exactly one pair of parallel sides.

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enrollment at Parker junior high is set to increased by 115% for the next school year if there are 340 students enrolled to this
trapecia [35]

Answer:

731

Step-by-step explanation:

to find out the percent you multiply 340 by 115% which will look like this 340 times 1.15 equals to 391

to find out how many students will enroll next year you add 340 and 391 and it equals to 731.  

7 0
3 years ago
Which undefined terms are needed to define parallel lines
Alexandra [31]
Parallel lines<span> are coplanar </span>lines<span> that do not intersect</span>
6 0
3 years ago
Write 1/5 as a fraction before it was reduced ​
Tanya [424]
2/10, or 5/25 can i get brainliest
i just multiplied the top n bottom number by the same number
7 0
3 years ago
For vectors u= (3,4) and v= (1,3) find CompuV and the angle between u and v.
vampirchik [111]

Answer:

The angle between the given vectors u and v is \theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]

Step-by-step explanation:

Given vectors are \overrightarrow{u}=(3,4) and \overrightarrow{v}=(1,3)

Now compute the dot product of u and v:

\overrightarrow{u}.\overrightarrow{v}=(3,4).(1,3)

  =(3)(1)+(4)(3)

  =3+12

 =15

Now find the magnitude of u and v:

|\overrightarrow{u}|=\sqrt{3^2+4^2}

=\sqrt{9+16}

=\sqrt{25}

=5

|\overrightarrow{u}|=5

|\overrightarrow{v}|=\sqrt{1^2+3^2}

=\sqrt{1+9}

=\sqrt{10}

|\overrightarrow{v}|=\sqrt{10}

To find the angle between the given vectors

\overrightarrow{u}.\overrightarrow{v}=|\overrightarrow{u}|\overrightarrow{v}|cos\theta

\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]

=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]

=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]

\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]

Therefore the angle between the vectors u and v is

\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]

3 0
3 years ago
Please help me! :) !!!!!!!!!!!!!!!!!
Novosadov [1.4K]

Answer:

x=17

Step-by-step explanation:

Since the triangles are congruent, the angles are equal

I≅ P  

3x+4 = 72-x

Add x to each side

3x+4+x = 72-x+x

4x+4 = 72

Subtract 4 from each side

4x+4-4 = 72-4

4x= 68

Divide by 4

4x/4 = 68/4

x = 17


7 0
3 years ago
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