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NARA [144]
3 years ago
11

Saturday Sunday Minutes 32 Miles 3 4 I

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
6 0
It’s droopy dog B homie it’s B
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Brainliest be good peeps Calculate the missing term in each and for 2 its not 6/7 it cant be okay? thanks tho if you try and get
omeli [17]

Answer:

The missing term is 10

Step-by-step explanation:

2/11=x/55

cross multiply

2*55=11x

x=10

I hope this helps :)

4 0
3 years ago
3^4x-5 = (1/27)^2x+10
Shtirlitz [24]

Answer:

x = 10935/59048 = 0.185

Step-by-step explanation:

27 = 3^3

(27)^2 = (33)^2 = 36

3 0
3 years ago
Someone please help I cannot figure this out PLEASE
sergejj [24]
Let the side of the square = a units,   the area of the square = a^2 sq units

Area of the 4 semicircles  = area of 2 circles = 2 pi r^2 =  2pi (1/2 a)^2
  =   pi a^2 / 2

Probability of a point in the unshaded square being picked)  = area square / area of the total figure  = a^2  / (a^2 * pi/2)   = 1 / pi/2 = 2 /pi

which is approximately  65%
8 0
4 years ago
The types of problems found on ancient papyri, books, and tablets focuses primarily on problems that relate to daily life. The s
Maksim231197 [3]

The <em><u>correct answer</u></em> is:

They had no placeholding zero.

Explanation:

Our numbering system is one of few known to have a numeral for zero. Mayans did; however, theirs never traveled the world. Babylonians were thought to have a mark for nothing, but it was more for punctuation than numerals. Neither the Romans nor the Egyptians had a number for 0 either.

Zero is key to our system of numbering, as it helps us hold place as well as representing nothing. Without it, it is easier to represent problems in words.

8 0
3 years ago
Read 2 more answers
Solve each inequality. <br> 1. 5x + 2 &lt;17
butalik [34]

Answer:

x<3

Step-by-step explanation:

5x+2<17

Subtract 2 from both sides.

5x<17−2

Subtract 2 from 17 to get 15.

5x<15

Divide both sides by 5. Since 5 is positive, the inequality direction remains the same.

x=15/5

Divide 15 by 5 to get 3.

x<3

8 0
3 years ago
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