Answer:3495250
Step-by-step explanation:
~geometric sequence
common ratio: r=4
formula: Sn=a1(1-r^n)/1-r
Sn=10(1-(4)^10)/1-4
=-10485750/-3
=3495250
Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
area = base times height, or 8 cm times 4 cm, or 32 cm^2
Answer:
=£1970
Step-by-step explanation:
10%=£360
5%=£190
40%=£1440
45%=£1630
£3600-£1630=£1970
