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Afina-wow [57]
3 years ago
12

PLSSS HELPPPPPPP CORRECT ANSWERS PLSSSS

Mathematics
2 answers:
Crank3 years ago
8 0

Answer:

-4.  (x+4)(x-4)

Step-by-step explanation:

Sidana [21]3 years ago
5 0

Answer:

-4  x+4 x-4

Step-by-step explanation:

CHARGE YOUR PHONE

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Question and choices are in the photo please explain the answer
Natasha_Volkova [10]

Answer:

\text{A) }68\:\mathrm{cm}

Step-by-step explanation:

The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.

Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.

To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a 90^{\circ}, creating right triangles \triangle TOP and \triangle SOP.

The Pythagorean Theorem states that the following is true for any right triangle:

a^2+b^2=c^2, where c is the hypotenuse, or the longest side, of the triangle

Thus, we have:

10^2+TP^2=26^2,\\TP^2=26^2-10^2,\\TP^2=\sqrt{576},\\TP=24

Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.

What we know:

  • TP=SP=24
  • TO=SO=10

Thus, the perimeter of the quadrilateral PTOS is equal to 24+24+10+10=\boxed{\text{A) }68\:\mathrm{cm}}

7 0
3 years ago
Read 2 more answers
Terry is making 5 hat and scarf sets. Each scarf requires 3 yards of material and each hat requires 18 inches of material. How m
Delvig [45]
5*18 = 90
5*3= 15

90+15= 105
4 0
2 years ago
The maximum height of a vehicle that can safely pass under a bridge is 12 feet 5 inches. A truck measures 162 inches in height.
Leni [432]
1 foot = 12 inches. If you multiply 12 by 12 and then add 5, you get 149. 149 is less than 162 so it will be able to fit!
8 0
3 years ago
Write an<br> equation of the circle with center (-4,5) and radius 8.
Verizon [17]

Answer:

(x+4)2+(y-5)2=8

6 0
3 years ago
Solve to inequality 5/6v &lt; 8/5
Anna35 [415]
\dfrac{5}{6}v \ \textless \  \dfrac{8}{5}\ \ \ |multiply\ both\ sides\ by\ \dfrac{6}{5}\\\\\dfrac{6}{5}\cdot\dfrac{5}{6}v \ \textless \  \dfrac{6}{5}\cdot\dfrac{8}{5}\\\\v \ \textless \  \dfrac{48}{25}\to v\in\left(-\infty;\ \dfrac{48}{25}\right)
4 0
3 years ago
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