The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :


We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
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Answer:
12.4
Step-by-step explanation:
do 9x11 (the cross)
then divide that by 8, so 99/8
that equals 12.375 which rounded to the nearest tenth is 12.4
Answer:
It's C
Step-by-step explanation:
It's C because when you find the least common denominator of 3 and 5 it's 15. So then you convert the fractions to get 6/15+5/15=11/15, which leaves 4/15 left.
Answer:
245=2.45
7/50=0.14
Step-by-step explanation:
divide by 100
USE MATHAWAY DOT COM!!
Answer:
ummm i dont know but try 16 35/21
Step-by-step explanation: