Question

Can someone please help me with this; im a lil bit confused.... Q.solve for the values of x in the equation 2x² - 5x - 12 = 0 using the quadratic equation formula.​

Answer 1

Answer:

The solutions for x are $x = 4$ and $x = -1.5$.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$.

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$, given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

2x² - 5x - 12 = 0

This means that $a = 2, b = -5, c = -12$

Solution:

$\Delta = (-5)^2 - 4(2)(-12) = 121$

$x_{1} = \frac{-(-5) + \sqrt{121}}{2*2} = 4$

$x_{2} = \frac{-(-5) - \sqrt{121}}{2*2} = -1.5$

The solutions for x are $x = 4$ and $x = -1.5$.