It is the sum of the integers from 1-41 minus the sum of the integers from 1-24 divided by 17
the sum of the integers from 1-41 is (42)(45)/2 = 861
the sum of the integers from 1-24 is (24)(25)/2 = 300
(861-300)/17 = 33
The answer is 33
Simplify 1/3(6x - 15) to 6x - 15/3
6x - 15/3 = 1/2(10x - 4)
Factor out the common term; 3
3(2x - 5)/3 = 1/2(10x - 4)
Cancel out 3
2x - 5 = 1/2(10x - 4)
Simplify 1/2(10x - 4) to 10x - 4/2
2x - 5 = 10x - 4/2
Factor out the common term; 2
2x - 5 = 2(5x - 2)/2
Cancel out 2
2x - 5 = 5x - 2
Subtract 2x from both sides
-5 = 5x - 2 - 2x
Simplify 5x - 2 - 2x to 3x - 2
-5 = 3x - 2
Add 2 to both sides
-5 + 2 = 3x
Simplify -5 + 2 to -3
-3 = 3x
Divide both sides by 3
- 1 = x
Switch sides
<u>x = -1</u>
Answer: provided in the explanation segment
Step-by-step explanation:
(a). from the question, we can see that since that б is known, we can use standard normal, z.
we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?
⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;
x ± z * б / √m
which is
3.15 ± 1.28 * 0.32/√10
= 3.15 ± 0.1295 = 3.0205 or 3.2795
(b). normal distribution of weight (c) б is known
(c). option (a) and (e) are correct
(d). from the question, let sample size be given as S
this gives';
1.28 * 0.32/√S = 0.15
√S = (1.28 * 0.32) / 0.15 = 2.73
S = 7.4529
cheers i hope this helps
Answer:
1.33 years.
Step-by-step explanation:
